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Lelechka [254]
3 years ago
6

Which relationship describes angles 1 and 2?

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0
Supplementary angle.
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Find the sum: 28,35,42,49,56,63,70
lianna [129]

Answer:

343

Step-by-step explanation:

Big brain calculator work

28 + 35 + 42 + 49 + 56 + 63 + 70 = 343

5 0
3 years ago
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The scale of a map is 1in.:75km. Determine the distance between two towns that are 5.6 in. apart on the map.
sergeinik [125]

Answer:

420 km

Step-by-step explanation:

75 times 5 = 375

75/10 = 7.5 times 6 = 45

375 + 45 = 420

6 0
3 years ago
Find the product. (-4·3·2)2 -48 48 -576 576
VLD [36.1K]
(-4*3*2)^2 = (-24)^2 = 576

hope this will help you 
5 0
3 years ago
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3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
3x-4y=-5 y=4x-2 Is (1,2) a solution of the system?
Orlov [11]
If you want to check if (1,2) is a solution to the system, you have to plug the x and y values back into both equations. If they work for one equation, but not the other, than the coordinates are not a solution to the system.

3(1) - 4(2) = -5
3 - 8 = -5
-5 = -5 

2 = 4(1) - 2
2 = 4 - 2 
2 = 2

Since both of these checks are true, then (1,2) is a solution to the system.
7 0
3 years ago
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