The value of x is 5/8.
<u>Step-by-step explanation</u>:
Given,
- The lines PQ and RS are parallel to each other.
- slope of PQ= x-1/4
- slope of RS = 3/8
The slopes of parallel lines are equal.
slope of PQ = slope of RS
⇒ x-1/4 = 3/8
⇒ (4x-1)/4 = 3/8
⇒ 8(4x-1) = 4(3)
⇒ 32x-8 = 12
⇒ 32x = 20
x = 20/32
x = 5/8
-4*3 1/4 would be and expression you can use
It is not direct variation because it does not follow the equation
y = slopex
THE points do not make the equation true .
Answer:
32 and 40
Step-by-step explanation:
Let's call the smaller number x. If the smaller number is x, the equation for this problem is 2x + 8 = 72
Equation:
2x + 8 = 72
2x = 64
x = 32
So now we know the smaller number is 32, so now add 8 and we get 40.
Therefore the 2 numbers are 32 and 40
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
