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3 years ago

Can someone help me out with this?

Mathematics

2 answers:

Citrus2011 [14]3 years ago

7 0

Use the app called M.a.t.h.w.a.y (just get rid of the dots. The app wont let me say what it is and calles it rude.) and you can use it for all of your math! It gives faster results and is free! No points or money!

Tanya [424]3 years ago

5 0

Answer:thats a triangle

Step-by-step explanation:

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Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

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2 years ago

State that dgree of the term -6x²y

vladimir2022 [97]

I think it’s -6 but I would check with someone else too lol

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3 years ago

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Vsevolod [243]

Answer:

Step-by-step explanation:

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Answer:

d = 1.5

Step-by-step explanation:

yes

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Nuetrik [128]

Answer:

the answer is B. 99x + 84 ≥ 1,150

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