Answer:
The dimension of the larger bin is x and the smaller bin is 
.
Step-by-step explanation:
Let the dimension of the larger bin is x.
It is given that the dimension of the smaller bin can be found by dilating the dimension of the larger bin by a scale factor of 0.75
In order to find the dimension of the smaller bin multiply the dimension of the larger bin by 0.75
Hence, the dimension of the larger bin is x and the smaller bin is .
30(or x)-8=22 I don't know if that is one of the answers or not
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Answer: 145 cans
Step-by-step explanation:
arithmetic sequence
aₙ = a₁ + (n-1).r
aₙ → last term
a₁ → 1st term
n → quantity of terms
r → common difference
a₁ = 1 (one can at the top)
aₙ₋₁ = 25
aₙ = 28
To find out How many cans are in the entire display, we need the SUM of the arithmetic sequence: S = (a₁+aₙ)n/2
∴
S = (1+28).n/2
n = ?
aₙ = a₁ + (n - 1).r
r = 28 - 25 = 3
28 = 1 + (n - 1).3
27 = (n - 1).3
27/3 = (n - 1)
9 = n - 1
n = 9 + 1 = 10
S = (1+28).n/2
S = (1+28).10/2 = 29.10/2 = 29.5 = 145
First off, your chances of red are not really 50-50. You are overlooking the 0 slot or the 00 slot which are green. So, chances of red are 18 in 37 (0 slot) or 38 (0 and 00 slots). With a betting machine, the odds does not change no trouble what has occurred before. Think through the simplest circumstance, a coin toss. If I toss heads 10 times one after the other, the chances of tails about to happen on the next toss are still on a 50-50. A betting machine has no ability, no plan, and no past.
Chances (0 slot) that you success on red are 18 out of 37 (18 red slots), but likelihoods of losing are 19 out of 37 (18 black plus 0). For the wheel with both a 0 and 0-0 slot, the odds are poorer. You chances of red are 18 out of 38 (18 red slots win), and down are 20 out of 38 (18 black plus 0 and 00). It does not really matter on how long you play there, the probabilities would always continue the same on every spin. The lengthier you play, the more thoroughly you will tie the chances with a total net loss of that portion of a percent in accord of the house. 18 winning red slots and either 19 or 20 losing slots.
