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GREYUIT [131]
3 years ago
14

Is 7n - 8m = 4-2m a linear equation? If so, put it in standard form.

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
What do you mean put in standard form?
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The dimensions for a rectangular prism are x + 3 for the length, x + 2 for the width, and x for the height. What is the volume o
lisabon 2012 [21]

Answer:

the answer will be x^3 + 2x^2 + 9x

Step-by-step explanation:

as :

volume = l* w* h

= X * (X + 2) * (X + 3)

= X ^ 2 + 2 X (X + 3)

= x ^2 (X + 3) + 2x (X + 3)

= x^3 + 3x +2x ^2 + 6x

= x^3 + 2x^2 + 9x

7 0
3 years ago
A company considers buying a machine to manufacture a certain item. When tested, 28 out of 600 items produccd by the machine wer
weqwewe [10]

Answer:

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject H_0, as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

Step-by-step explanation:

The null and alternate hypothesis are:

H0:p≥0.03

Ha:p<0.03

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis:

This means that \mu = 0.03, \sigma = \sqrt{0.03*0.97}

28 out of 600 items produced by the machine were found defective.

This means that n = 600, X = \frac{28}{600} = 0.0467

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.0467 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{600}}}

z = 2.4

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.0467, which is the p-value of z = 2.4.

Looking at the z-table, z = 2.4 has a p-value of 0.9918.

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject H_0, as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

7 0
3 years ago
6,500 cL = how many L
TiliK225 [7]
There are 65 Liters in 6500 centiliters.

1 cl = 0.01 L, so 0.01 x 6500 = 65
5 0
3 years ago
Read 2 more answers
Plase help me thanks you!
sasho [114]
$12 x .30= $3.60 mark up so new price was $15.60.

$15.60 x .25= $3.90 discount, so the new price with discount would be $11.70
3 0
2 years ago
Read 2 more answers
Based on the model ​N(11541154​,8686​) describing steer​ weights, what are the cutoff values for ​a) the highest​ 10% of the​ we
yaroslaw [1]

Answer:

a) x = 1225.68

b) x = 1081.76

c)  1109.28 < x < 1198.72

Step-by-step explanation:

Given:

- Th random variable X for steer weight follows a normal distribution:

                                    X~ N( 1154 , 86 )

Find:

a) the highest​ 10% of the​ weights? ​

b) the lowest​ 20% of the​ weights? ​

c) the middle​ 40% of the​ weights? ​

Solution:

a)

We will compute the corresponding Z-value for highest cut off 10%:

                                   Z @ 0.10 = 1.28

                                    Z = (x-u) / sd

Where,

u: Mean of the distribution.

s.d: Standard deviation of the distribution.

                                   1.28 = (x - 1154) / 86

                                      x = 1.28*86 + 1154

                                      x = 1225.68

b)

We will compute the corresponding Z-value for lowest cut off 20%:

                                   -Z @ 0.20 = -0.84

                                    Z = (x-u) / sd

                                   -0.84 = (x - 1154) / 86

                                      x = -0.84*86 + 1154

                                      x = 1081.76

c)

We will compute the corresponding Z-value for middle cut off 40%:

                                    Z @ 0.3 = -0.52

                                    Z @ 0.7 = 0.52

                                    [email protected] < x < [email protected]

                       -.52*86 + 1154 < x < 0.52*86 + 1154

                                  1109.28 < x < 1198.72

7 0
3 years ago
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