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3 years ago

Find the mean of the data set. if necessary, round to the nearest tenth. 18 14 8 22 25 8

1 answer:

6 0

To work out the mean of a data set add all the numbers together and divide them by the number of data items there are.

18 + 14 + 8 + 22 + 25 + 8 = 95

95/6 = 15.8 (that answer is rounded)

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188 ASU students, faculty and staff were randomly surveyed and asked if they have an ASU parking decal, ride their bike to campu

bulgar [2K]

Part A.
The venn diagram is attached. In the venn diagram, circle A represent the number of responds that have an ASU parking deal. Circle B represent the number of respondents that ride their bike to campus and circle C represent the number of respondents that that ride the Light Rail.

Part B.
From the venn diagram, the number of respondents that ride the Light Rail and ride their bike to campus is given by 39 – 12 = 27

Part C.
From the venn diagram, the number of respondents that only have an ASU parking decal is given by 77 – 12 – 8 – 6 = 51

Part D.
The number of respondents that ride the Light Rail or have an ASU decal is given by the sum of the number of respondents that ride the Light Rail only and those that have an ASU parking decal and those that have both ASU parking decal and ride their bike to school.
This is given by 51 + 8 + 28 = 87.

Part E.
The venn diagram showing the area that represents people who have a parking decal or who ride their bike to campus but who do not ride the Light Rail sgaded is attached.

8 0

3 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

2 years ago

The first time a census was taken in Esinville, the population was 12,621. Each year after that, the population was about 6% hig

Sedbober [7]

Step-by-step
Population was 12.621 when it was measured

Next year it rose by 6%, so add that 6% to 100% and multiply with population measured

12.621 × (100%+6%) = 12.621 × 106% = 13.379,24

Since a man cant be 0,24, we count that as +1

13.379,24 = 13.379 + 1 = 13.380

That was for a year after measurement, now let's calculate for another year
Now, add those 6% to a new population number

13.380 × (100%+6%) = 13.380 × 106% = 14.182,8

since 0,8 isn't a man, instead we add again +1

14.182,8 = 14.182 + 1 = 14.183

now let's do it for another year after last, by adding those 6% to a newest population number

14.183 × (100%+6%) = 14.183 × 106% = 15.033,98

round it again to +1, since 0.98 isn't a man

15.033,98 = 15.033 + 1 = 15.034

that is it, now graph is in the picture.

8 0

3 years ago

Factor the polynomial. 7x2 + 68xy - 20y2 A) (7x - 2y)(x + 10y) B) (7x - 10y)(x - 2y) C) (7x + 10y)(x + 2y) D) (7x + 2y)(x - 10y)

Otrada [13]

For this case we have the following polynomial:
7x2 + 68xy - 20y2
Factoring we have:
(7x-2y) (x + 10y)
We verify the factorization:
7x2 + 70xy - 2xy - 20y2
Rewriting we have:
7x2 + 68xy - 20y2
Therefore, the factorization is correct.
Answer:
A) (7x - 2y) (x + 10y)

5 0

3 years ago

F(x) = 6x +1, find f (4c+2) 24c - 13 O 18c + 1 240 + 13 240 + 1

postnew [5]

Answer:C 5a^2 +70a +240

Step-by-step explanation:

8 0

2 years ago