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3 years ago

Y ≤ -2x + 4. What points satisfy the inequality?

1 answer:

6 0

Subtract 4 from both sides
y−4≤−2x

Divide both sides by −2
- y-4/2 ≥ x

Switch sides
x ≤ − y−4/2

HOPE THIS HELPS!!

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The square shown has a perimeter of 32 units. The square is rotated about line k. What shape is created by the rotation and what

harkovskaia [24]

The perimeter of the square is calculated through the equation,
4x = P
where P is the perimeter and x is the measure of the sides.

When P is 32 units then,
32 units = 4(x)
x = 8 inches

This 8 inches is the diameter of the cylinder formed by the rotation.
The circumference of the base is calculated through,
C = 2πr = πD
Substituting the known values,
C = π(8 units) = 8π units
When π is equal to 3.14, we solve for the numerical value of the cylinder as follows,
 C = 8(3.14) = 25.12 units
Thus, the figure formed is a cylinder with base circumference equal to 25 units. The answer is the third choice.

6 0

3 years ago

Read 2 more answers

What is the slope-intercept form for y – 6 = 3 ( x− 1/3 )

Leviafan [203]

Answer:

y=3x+5

Step-by-step explanation:

This is th eanswer because slope intercept form is always y=mx+b.

So, if you simplify the right side of the equation, you then get

y-6=3x-1, I got that because 3 multiplied by -1/3, you get -1.

Then you add 6 to both sides to isolate y by itself. So, now you have

y=3x+5.

Hope this is helpful

5 0

3 years ago

On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is

OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.

$P(x,y)$ - Original point.

$k$ - Scale factor.

$P'(x,y)$ - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

( $P(x,y) = (10, 40)$ , $Q(x,y) = (70, 120)$ , $O(x,y) = (0,0)$ , $k = 5$ )

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$

$P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]$

$P'(x,y) = (50,200)$

$Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]$

$Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]$

$Q'(x,y) = (350, 600)$

Then, the length of the resulting segment is determined by following Pythagorean identity:

$l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}$

$l_{P'Q'} = 500$

The length of the resulting segment is 500.

3 0

3 years ago

Factor the expression below.

OverLord2011 [107]

Answer:

(x + 8) (x - 8)

Step-by-step explanation:

To factorise the expression follow the steps:

Think the factorising means you want like:-

( x + _ ) ( x + _ )

Now, add the numbers to get 0 & multiple together to get -64

-64 = 8 x -8

8 + -8 = 0

Now fill the numbers in the factorising mean which will give you,

( x + _ ) ( x + _ ) --> ( x + 8 ) ( x - 8 )

Therefore, the answer will be: ( x + 8 ) ( x - 8 )

I hope this will help you :)

4 0

3 years ago

After losing your job, and needing cash fast, you decide to try

ra1l [238]

Given:

The principal = $ 4000

The rate of interest = 22 %

To find the loan amount a) after 1 year and b) after 3 years.

Formula

Loan amount is

$A = P(1+\frac{r}{100} )^{t}$

where,

A be the loan amount

P be the principal

r be the rate of interest and

t be the time.

Now,

a) Taking, P = 4000, r = 22, t = 1 we get,

$A = 4000 (1+\frac{22}{100} )^{1}$

or, $A = 4880$

Again,

b) Taking, P = 4000, r = 22 and t = 4 w eget,

$A = 4000(1+\frac{22}{100})^{4}$

$or, A = 7263.39$

Hence,

a) The amount of loan after 1 year is $ 4880

and b) The amount of loan after 4 year is $ 7263.39.

8 0

2 years ago