The statement that explains how the company can determine whether pool LMNO is similar to pool PQRS is;
B. Translate PQRS so that point Q of PQRS lies on point M of LMNO, then dilate PQRS by the ratio segment PQ over segment LM.
<h3>How to carry out Transformations?</h3>
Given that quadrilaterals ABCD and EFGH are similar:
The corresponding points on the quadrilaterals are:
P → L
Q → M
R → N
S → O
So, the first step is any of the following:
Translate point P to L
Translate point Q to M
Translate point R to N
Translate point S to O
Notice that the side lengths of PQRS are bigger than that of LMNO
This means that the Quadrilateral PQRS has to be dilated (compressed) by a ratio of side lengths of LMNO divided by side lengths of PQRS
For example, the point M is translated to point Q. The figure will then be dilated by a ratio of LM divided by PQ.
Read more about Transformations at; brainly.com/question/4289712
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Answer:
Step-by-step explanation:
15x-35x
25x is the answer
Answer:
the answers are:x1=-4 and x2=5
Answer:
x ≤ 6 and x ≥ 2
Step-by-step explanation:
For now, we will start with doing each problem at a time. Here is your equation:
2x - 4 ≤ 8
First, you want to get the variable by itself. So, you add 4 to both sides. It will look like this:
2x - 4 ≤ 8
+ 4 + 4
The four being added on the left side cancels out, and you add 4 to 8. Now, it should look like this:
2x ≤ 12
Next, you want the x by itself. So, you would divide both sides by 2.
2x ≤ 12
/2 /2
2 divided by 2 cancels out, and 12 divided by 2 equals 6. Now, you have a final answer of:
x ≤ 6
But, you now have to do the other one!
Here is what you start off with:
x + 5 ≥ 7
First, you want the variable side by itself. So, you subtract 5 from both sides.
x + 5 ≥ 7
- 5 -5
Now, you have this:
x ≥ 2
Because the variable is already by itself, you don't need to do any more division and this is you final answer. Now put both answers you got together which equals:
x ≤ 6 and x ≥ 2
Answer:
Step-by-step explanation:
let wind velocity=x
speed of plane=y
(x+y)*4=808
x+y=808/4=202 ...(1)
(y-x)*4=488
y-x=122 ...(2)
add (1) and (2)
2y=202+122=324
y=324/2=162
from (1)
x+162=202
x=202-162=40
wind velocity=40 m/hr
speed of plane=162 m/hr
