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liubo4ka [24]
3 years ago
11

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

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Answer:

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Step-by-step explanation:

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51÷3 = k

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Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 28 meters
11Alexandr11 [23.1K]
The perimeter is given by:
 P = 2x + 2y = 28
 The area is given by:
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Marsha recorded the time it took seven children of different ages to run one lap around the track.
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The answer is C. 205.
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Charlie is a car salesman. He earns $800 plus a 9% commision on all of his sales for the week. If charlie received a paycheck fo
Hunter-Best [27]

Question

Charlie is a car salesman. He earns $800 plus a 9% commision on all of his sales for the week. If charlie received a paycheck for $1916 this week, how much were his total sales?


Answer:

<h2>1240</h2>

Step-by-step explanation:

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1116 : 9 * 100 =

1240



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3 years ago
The arithmetic sequence a_ia i ​ a, start subscript, i, end subscript is defined by the formula: a_1 = 15a 1 ​ =15a, start subsc
daser333 [38]

Answer:

-1,512,390

Step-by-step explanation:

Given

a1 = 15

a_i = a_{i-1} -7

Let us generate the first three terms of the sequence

a_2 = a_{2-1}-7\\a_2 = a_1 - 7\\a_2 = 15-7\\a_2 = 8

For a_3

a_3 = a_{3-1}-7\\a_3 = a_2 - 7\\a_3 = 8-7\\a_3 = 1

Hence the first three terms ae 15, 8, 1...

This sequence forms an arithmetic progression with;

first term a = 15

common difference d = 8 - 15 = - -8 = -7

n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)

Using the formula;

S_n = \frac{n}{2}[2a + (n-1)d]\\

Substitute the given values;

S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390

Hence the sum of the first 660 terms of the sequence is  -1,512,390

6 0
3 years ago
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