3 years ago

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Mathematics

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

You might be interested in

Please look a the pic<br><br> also you need to find the area

iogann1982 [59]

Answer:

area of circle is 113.04 (i used 3.14 for pi) 3.14 x 6^2

area of square is 24 - 12 x 2 = 24

area of square without circle is 89.04 - 113.04 - 24 = 89.04

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Choose the simplified solution(s) to this equation: ?- 128 - 0 18 1642 V128 18/2 Question 33 )

tatiyna

D is correct answer

±8√2

7 0

2 years ago

[Question Deleted 5/15/2021]

pav-90 [236]

[Question Deleted 6/15/2021]

lets play this

anyone can do it ima go to sleep lol

7 0

3 years ago

A car park is full. 1/3 of the cars leave.60% of the cars are red. There are 174 red cars. How many cars are left in the car par

juin [17]

Answer:

290

Step-by-step explanation:

60% of ⅔X = 174

60/100 × 2/3 × X = 174

⅖X = 174

X = 435

⅔X = ⅔×435

290

290 cars are left in the parking,

145 cars left

5 0

3 years ago

Read 2 more answers

If ps=6cm and pt=9cm what is pr

vladimir1956 [14]

$16+ x^{2} = 36
$
$x^{2} =20$
$x= \sqrt{20}$
$4^{2} + x^{2} = 6^{2} 
$

Hope it helps!
#MissionExam001

4 0

3 years ago