Answer:
a) positive direction: t < 2s & t>6s ; negative direction: 2s < t < 6s
b) 7 m
c) 71 m
Step-by-step explanation:
Given:
v(t) = 3t^2 -24t +36 [0 , 7]
Find:
a) The value of time when particle is moving in positive direction:
The change in direction of the particle can be determined by v(t) > 0
Hence,
0 < 3t^2 -24t +36
0 < t^2 - 8t + 12
0 < (t - 2)*(t - 6)
t < 2s , t > 6s
The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.
b) The displacement ds over the given interval [ 0 , 7 ]
ds = integral (v(t)).dt
ds = t^3 -12t^2 +36t
ds = 7^3 -12*7^2 +36*7
ds = 7 m
c) Total distance traveled in the interval:
Total distance= ds(0-2) + ds(2-6) + ds(6-7)
D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7
D = 2*32 - 2*0 + 7
D = 71 m
Answer: x = {-2, 2}
<u>Step-by-step explanation:</u>
Tangent means it is touching. Find the intersection of the two equations.
Solve the linear equation for y, then set the two equations equal to each other.
To find the next point that is parallel to the linear equation and tangent to the curve, we need to use the linear equation with slope (m) = 
and unknown b.
Let's try b = 0, then the equation of the linear equation is: 
Set the equations equal to each other and solve for x:
This works!!! If it didn't work, we would have tried other values for b until we arrived at a solution.
It’s about 141.37. Here’s the equation: V=πr2h=π·32·5≈141.37167
<span>To find the number of passengers for the next year (2002), take the prior value (7.2 million) and multiply it by 1.09. This will give the predicted value for 2002. In this case, it would be (7,200,000 * 1.09 = 7.848 million). This would show that there is a predicted rise of 0.648 million passengers for the year 2002.</span>
