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ASHA 777 [7]
4 years ago
6

The length of a rectangle is represented by (6x − 2), and the width is represented by (x − 1). Which expression best represents

the area of the rectangle
Mathematics
1 answer:
Dmitriy789 [7]4 years ago
4 0

Answer:

The answer is 6x^2-8x+2

Step-by-step explanation:

To find the area, you have to multiply the length by the width.

You will get the equation of (6x-2)(x-1). Then, you multiply and find the answer, 6x^2-8x+2.

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3. Suppose U= {1,2,3,4,5,6,7,8,9,10} is the universal set and Q= {3,6,9}. What is Q'?
Readme [11.4K]

Answer:

3. Q' = {1 , 2 , 4 , 5 , 7 , 8 , 10} ⇒ answer C

4. A ⊂ B is False ⇒ answer B

Step-by-step explanation:

3.

- The universal set U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10}

- The set Q = {3 , 6 , 9}

- We need to find the complement of set Q (Q')

- The complement set of Q is the set of all elements belongs to the

 universal set U but does not belong to the set Q

- That means take off all the elements belongs to set Q from the

  universal set U

∵ U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10}

∵ Q = {3 , 6 , 9}

- Cancel from set U the elements 3 , 6 , 9

∴ Q' = {1 , 2 , 4 , 5 , 7 , 8 , 10}

4.

- The universal set U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8}

- The set A= {1 , 3 , 5 , 7}

- The set B= {4 , 5 , 6}

- A ⊂ B means every element in set A belongs to set B

∵ A= {1 , 3 , 5 , 7}

∵ B= {4 , 5 , 6}

∵ The elements in set A ∉ in set B

∴ A ⊂ B is False

7 0
3 years ago
Using elimination (add or sub) find the solution to the following system of equations 5x+ 3y=9 2x -3y=5
Levart [38]
5x+3y=9
2x-3y=5

5x+2x=9+5
7x=14
14/7x= 2
x=2

sub it in so you get y

5(2)+3y=9
10+3y=9 (-10 to get rid of it)
3y=-1
3y/-1= - 1/3

x= 2 y= - 1/3
8 0
3 years ago
What’s the answer to this question
USPshnik [31]
It is 62 inch squared.

All you have to do is plug the numbers into the SA formula (SA= lw + hw + hl)
7 0
3 years ago
Read 2 more answers
Determine the solutuon for x^2-3x-28>0
natita [175]

Answer:

 x < -4 or x > 7.

Step-by-step explanation:

We first determine the critical points by solving x^2 - 3x - 28 = 0:

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x = 7, - 4

so the critical points are  -4 and  7.

Create a Table   (pos = positive and neg = negative):

Value  of           x< - 4        -4  < x < 7         x > 7    

---------------------|----------- |--------------------- |---------------------

x + 4                  NEG           POS                 POS

x - 7                    NEG           NEG                POS

(x + 4)(x - 7)         POS           NEG                POS

So the function is positive (>0) for x < -4 or x > 7.

You can also do this by drawing the graph of the function.

6 0
3 years ago
Of the following points, name all that lie on the same vertical line?
Masteriza [31]

Answer:

(-2,-6) (6,2)

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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