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frutty [35]
3 years ago
13

How can you rename a whole number?

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0
I will give you an example of a whole number that we can rename easily.
253 can be represented as:
253 ones2 hundreds 5 tens 3 ones
2 hundreds 53 ones25 tens 3 ones
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Someone help real quick
ValentinkaMS [17]

Answer:

Step-by-step explanation:

From the graph <em>f</em>(-2) = 0

g(-2) = -3(-2) + 2

= 6 + 2 = 8.

So f(-2) is less than g(-2).

2. From the graph the y-intercept of f(x) = 8.

To find the y-intercept of g(x) solve y = -3x +2 when x = 0:

y = -3(0) + 2 = 2.

So f(x) has a greater y-intercept than g().

6 0
3 years ago
WILL GIVE BRAINLEST
WITCHER [35]

Answer:

Height ... just took the test

Step-by-step explanation:

8 0
3 years ago
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Please help!! ALgebra 2 <br> I will be h=giving out extra points the the brainiest answers
Arte-miy333 [17]

Answer:

B

Step by Step Explanation

4 0
2 years ago
The sales tax rate is 4.3064.306​% for the city and 44​% for the state. Find the total amount paid for 33 boxes of chocolates at
svp [43]

Answer:

The Total amount of of 33 boxes of chocolates including taxes is $838.358

Step-by-step explanation:

Given as :

The sales tax rate for city = 4.306%

The sales tax rate for the state = 44%

Total number of boxes = 33

The price of each chocolates = $17.13

So , The price of 33 boxes of chocolates = $17.13 × 33

I.e The price of 33 boxes of chocolates = $565.29

Now total tax including state and city =  4.306% + 44% = 48.306 %

So, The tax amount paid for 33 boxes of chocolates = 48.306 % of $565.29

∴    The tax amount paid for 33 boxes of chocolates = 48.306 % × $565.29

                                                                       = 0.48306× $565.29

                                                                       = $273.068

∴ The Total amount of of 33 boxes of chocolates including taxes = $565.29 +  $273.068 = $838.358

Hence The Total amount of of 33 boxes of chocolates including taxes is $838.358 . Answer

4 0
3 years ago
The figure below shows a rectangle ABCD having diagonals AC and DB: A rectangle ABCD is shown with diagonals AC and BD. Jimmy wr
yaroslaw [1]

Answer:

C. DC = DC. By reflexive property of equality.

Step-by-step explanation:

We are given that,

In step 4, Jimmy proved ΔADC ≅ ΔBCD by the SAS Congruence Postulate.

For that, the previous steps states,

Step 1: AD = BC, as opposite sides of a rectangle are congruent.

Step 2: ∠ADC = ∠BCD

So, in order to satisfy the SAS Postulate, we must have another pair of sides equal from the respective rectangles.

As, we can see that in ΔADC and ΔBCD, the side DC is a common side.

Thus, in the missing step, we get,

Step 3: DC = DC, By the reflexive property of equality.

Hence, option C is correct.

5 0
3 years ago
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