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Georgia [21]
3 years ago
11

Can anyone help me with this​

Mathematics
1 answer:
yaroslaw [1]3 years ago
5 0

Answer:

answer is 11 feet is the correct answer

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What pair of fractions is 0.8 between on a number line
madam [21]
0.8  has one decimal.. so... let's make it a fraction first, by using one zero with a one as denominator.

\bf 0.\underline{8}\implies \cfrac{08}{1\underline{0}}\impliedby \textit{one decimal, one zero, no dot}
\\\\\\
\cfrac{8}{10}\implies \cfrac{4}{5}
\qquad \qquad \qquad 
......\cfrac{1}{5}..\cfrac{2}{5}..\cfrac{3}{5}..\boxed{\cfrac{4}{5}}..\cfrac{5}{5}..\cfrac{6}{5}..\cfrac{7}{5}......

is between any of those, among many other fractions as well.
3 0
3 years ago
(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^
Sedbober [7]
Hello,

a)
I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\

= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\

=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\

= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\
= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\


I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\
I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\


b)
\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\
= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\
= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\






\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\
= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\







c)

I_n=  \dfrac{n-1}{n} * I_{n-2} \\

I_{2n+1}=  \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\
= \dfrac{2n}{2n+1} * I_{2n-1} \\
= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\
= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\

I_1=1\\






3 0
3 years ago
AActiveWhich is the graph of g(x)=[²]* - 2²(0,2.25)2--2Mark this and return2 3Save and Exit56NextSubmit
bogdanovich [222]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given function

g(x)=(\frac{2}{3})^x-2

STEP 2: Plot the given function

STEP 3: choose the correct graph

It can be seen from the plotted graph in step 2 that:

\begin{gathered} x-intercept:(-1.71,0) \\ y-intercept:(0,-1) \end{gathered}

Hence, comparing the x-intercepts, the correct graph is seen in:

3 0
1 year ago
They want me to start with one triangle and add 2 tooth picks each time but how do I do that
navik [9.2K]
Add them all around the top pointing down
6 0
3 years ago
Read 2 more answers
Write the phrase as a rate in simplest form. $406 for 38 pieces
Anna71 [15]

Answer:

Rate will be $10.68/-

Step-by-step explanation:

For 38 pieces we have price $406

For 1 piece= 406/38 = 10.68

The rate will be $10.68/-

6 0
3 years ago
Read 2 more answers
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