Answer:
B. Yes; the domain values are at regular intervals and the range values have a common factor 4.
Step-by-step explanation:
I calculated it logically
Answer:
3/10
Step-by-step explanation:
There are 20 marbles. 6 of them are blue.
P = 6/20 = 3/10
Luktdkilfdiykfg;oizxkuilouyk7it8rl,kvkuc kugc ulv lug
Answer:
The length of the shorter piece=0.35 m
Step-by-step explanation:
Let the lengths be as follow;
Shorter piece=x
Longer piece=15 cm longer than twice shorter piece(x)
Since 1 m=100 cm, 15 cm=15/100=0.15 m
Longer piece= (2×x)+0.15=2x+0.15
Total length=1.2 m
Total length=shorter piece+longer piece
Replacing;
1.2=x+2x+0.15
3x=1.2-0.15
3x=1.05
x=(1.05/3)=0.35
The length of the shorter piece=x=0.35
Answer:

Step-by-step explanation:
The expression to transform is:
![(\sqrt[6]{x^5})^7](https://tex.z-dn.net/?f=%28%5Csqrt%5B6%5D%7Bx%5E5%7D%29%5E7)
Let's work first on the inside of the parenthesis.
Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Therefore ![\sqrt[6]{a} = a^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now let's replace
with
which is the algebraic form we are given inside the 6th root:
![\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E5%7D%20%3D%20%28x%5E5%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now use the property that tells us how to proceed when we have "exponent of an exponent":

Therefore we get: 
Finally remember that this expression was raised to the power 7, therefore:
[/tex]
An use again the property for the exponent of a exponent: