25 x 4= 100 so you would do this 3 times because you would do
25 x 4 + 25 x 4 + 25 x 4= 300
Answer:
Part A: 2k(2c2+5(2)-8c-20)
Part B: sorry i don't know how to do this part
Step-by-step explanation:
Part A, you divide each number by 2 first so you get a simplified version of each number. Then, you will quickly realize that the varible k is similar in all of the numbers then you remove that and put it with the 2 outside the (). Hope you understood my explination.
To figure ut the roots use the quadratic formula
x = [-b +- sqrt(b^2-4ac)]/2a
x = [-k +- sqrt(k^2-4(1)(5)]/2(1)
x = [-k + sqrt(k^2 - 20)]/2 or [-k - sqrt(k^2 - 20)]/2
So the question says these roots differ by sqrt 61, so let's subtract each
[-k + sqrt(k^2 - 20)]/2 - [-k - sqrt(k^2 - 20)]/2
well the k's cancel in the beginning and we are left with 2sqrt(k^2 - 20)/2, and the 2 on top and bottom reduce to
sqrt(k^2 - 20), so this equals sqrt 61
Set equal and solve
sqrt(k^2 - 20) = sqrt(61)
k^2 - 20 = 61
k^2 = 81, so k = +9 or -9
The greatest value therefore is k = +9.
Answer:
$4.35
Step-by-step explanation:
Knowns:
Total bill: $29.00
Tip of 15% ($29.00)
Work:
$29.00 (0.15) = $4.35 tip
Hope this helps!
<span>9/5C + 32 =
= 9/5 * 20 + 32
= 36 + 32
= 68
20 C = 68 F
</span>