Answer:
in steps
Step-by-step explanation:
DE // BC
m∠ADE = m∠ABC and m∠AED = m∠ACB
∴ ΔADE similar to ΔABC
AB/AD = AC/AE
(AD + DB) / AD = (AE + EC) / AE
AD/AD + DB/AD = AE/AE + EC/AE
1 + DB/AD = 1 + EC/AE
DB/AD = EC/AE (AD/DB = AE/EC)
Answer:
i hope number c is correct answer
Answer:
Speed of plane in air is 352 km/hr and speed of wind is 34 km/hr
Step-by-step explanation:
Average speed of plane in with wind = 386 km/h
Average speed of plane against wind = 318 km/hr
Consider the speed of plane in wind be x km/hr and speed of plane against wind be y km/hr
As such speed of plane in wind would be x + y km/hr and speed of plane against wind would be x - y km/hr. i.e
x+y = 386
x-y = 318
by solving these two equation, we get
2x=704
x= 352 km/hr
y=386 - 352
y= 34 km/hr
Hence, Speed of plane in air is 352 km/hr and speed of wind is 34 km/hr
Answer:
for part b the vertex is (2, 13)
Step-by-step explanation:
no (ice)
First combine like terms:
14d+-2d=12d
Then do -84 divided by 12 = -7
D= -7
