To solve using completing square method we proceed as follows:
x^2-10x+8=0
x^2-10x=-8
but
c=(b/2)^2
c=(10/2)^2=25
thus we can add this in our expression to get
x^2-10x+25=8+25
factorizing the LHS we get:
(x-5)(x-5)=33
(x-5)^2=33
getting the square roots of both sides we have:
x-5=+/-√33
x=5+/-√33
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Answer:
Number line A.
Step-by-step explanation:
|-5x| - 11 = -1
Add 11 to both sides.
|-5x| = 10
-5x = 10 or -5x = -10
x = -2 or x = 2
Answer: Number line A.
Answer:
The value of x = 13cm and y = 12cm.
Step-by-step explanation:
P is the exterior point to the circle with centre O
Radius = 5cm
Length of the tangent = 12 cm
Distance between the point and centre of the circle = x cm
We know that
The angle between the radius of the circle and the tangent at the point of contact is 90°
By Pythagoras Theorem
Hypotenuse² = Side²+Side²
⇛x² = 12²+5²
⇛x² = 144+25
⇛x² = 169
⇛x² = 13²
<h3>⇛x = 13 cm</h3>
We know that
The lengths of tangents drawn from the exterior point to the circle are equal.
<h3>y = 12 cm</h3>
<u>Answer</u><u>:</u> The value of x=13cm and y = 12cm.
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Step-by-step explanation: