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Tresset [83]
3 years ago
9

How many positive two-digit integers are factors of both 100 and 150?

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

There are 3 positive 2 digit integers that are factors of both 100 and 150

Step-by-step explanation:

Factors of 100:

1, 2, 4, 5, 10, 20, 25, 50, 100

Factors of 150:

1, 2, 4, 5, 6, 10, 15, 25, 30, 50, 75, 150

Common factors between these numbers:

1, 2, 4, 5, 10, 25, 50

Common factors that are positive 2 digit integers:

10, 25, 50

There are 3 positive 2 digit integers that are factors of both 100 and 150

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3 years ago
The table shows the amount of sugar needed to make lemonade. Are the quantities proportional? Explain which method you used and
Klio2033 [76]

Answer: Yes

Step-by-step explanation:

For the first sugar and servings part, 4 for sugar, 2 for servings.

The ratio for this example above it for sugars to servings it 2:1. So every 2 sugars is every 1 serving and this applies to every other of the sugars and servings in the table.

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2 years ago
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If 2^5 x 5^2 = 2^n x 10^2, what is the value of n?
Marat540 [252]

Answer: x = 0

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

7 0
3 years ago
Can someone please help me ASAP​
deff fn [24]

Answer:

QR = 17 cm

Step-by-step explanation:

Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then

TS = 5 cm and PT = 2 × 5 = 10 cm

So PS = 10 + 5 = 15 cm

PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm

Using the right triangle formed calculate QR using Pythagoras' identity

QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )

QR = \sqrt{289} = 17

3 0
3 years ago
Suppose f(7) = 5​, f'(7) = 8​, g(7) = 3​, and g'(7) = 4. Find h(7) and h'(7)​, where h(x ) = 4f (x) + 3g(x).
dusya [7]

Answer:

h(7) = 29

h'(7) = 44

Step-by-step explanation:

If h(x) =4f(x)+3g(x), to find h(7) we can substitute the values of f(7) and g(7) and we get:

h(7)=4f(7)+3g(7)\\h(7)=4(5)+3(3)\\h(7)=20+9\\h(7)=29

To find the derivative, we know that the derivative of a sum of functions equals the sum of the derivatives of those functions.

This would mean that h'(x)=4f'(x)+3g'(x), we can substitute the values for f'(7) and g'(7)

h'(7)=4f'(7)+3g'(7)\\h'(7)=4(8)+3(4)\\h'(7)=32+12\\h'(7)=44

7 0
3 years ago
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