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hammer [34]
3 years ago
13

What is the equation of the line that passes through the point (6,14) and is parallel to the line with the following equation? y

=-4/3x-1
Mathematics
1 answer:
Korolek [52]3 years ago
4 0

Answer:

\displaystyle \boxed{y = -1\frac{1}{3}x + 22}

Step-by-step explanation:

<em>Parallel</em><em> </em><em>Equations</em><em> </em>have SIMILAR <em>RATE OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], so keep \displaystyle -\frac{4}{3}as is and do this:

14 = −4⁄3[6] + b

14 = −8 + b

+ 8 + 8

_________

\displaystyle 22 = b \\ \\ y = -1\frac{1}{3}x + 22

I am joyous to assist you at any time.

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What is (6-6)+7x7+4= ?
laiz [17]
<h2>Anser</h2>

53

Step-by-step explanation:

(6-6)+7×7+4

=0+7×7+4

=7×7+4

=49+4

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8 0
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there are 40 black balls this is 4 more than twice the number of yellow balls how many yellow boll are there​
miss Akunina [59]

Answer:

There are 5 yellow balls

Step-by-step explanation:

40/4 = 10

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Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
2 years ago
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I believe its 4 we haven't really went over it
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3 years ago
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