There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
Learn more about combinations at brainly.com/question/11732255
#SPJ1
Answer:
x>50
Step-by-step explanation:
In order from greatest to least, the ribbons go
7/8 (Green)
3/4 (Pink)
1/3 (Blue)
This because 7 out of 8 is a larger number than 3 out of 4, and 3 out of 4 is greater than 1 out of 3.
we are given

we can use factoring formula

we can compare
and we get


now, we can solve for m and n
and we get

now, we can use formula
and we get

now, we can set it equal to 0





so, we will get
.............Answer
Answer:
See below
Step-by-step explanation:
Two lines are parallel if they have the same slope but different y-intercepts. So the slope that can be formed given the points (-3,6) and (9,2) is (9-(-3))/(2-6)=12/-4=-3
With y=-3x+b, we need b, which can be found by plugging in either point:
2=-3(9)+b
2=-27+b
29=b
So the y-intercept therefore cannot be 29 but it can be any real number.
So the equation y=-3x+2 works, y=-3x+3, y=-3x+4, and so on....