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icang [17]
2 years ago
13

$8.50 yoga mat; 75% markup

Mathematics
1 answer:
Alenkinab [10]2 years ago
3 0
The answer is:
14.875
Hope this helps
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How does the surface area of the two separate figures differ from the surface area of the composite figure? Explain your answer.
Crazy boy [7]

Answer:

here is what is the surface area of composite figure

Step-by-step explanation:

To calculate the surface area of a 3D composite object, find the outside surface area of each object and then add the surface areas together. It could also be broken into one on top and one on the bottom. Determine the surface area of the outside faces of the right prism.

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Math Simplify the expression ​
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\bf \cfrac{1}{x-10}\div\cfrac{9x}{x^2-9x-10}\implies \cfrac{1}{x-10}\cdot \cfrac{x^2-9x-10}{9x} \\\\\\ \cfrac{1}{\begin{matrix} x-10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\cdot \cfrac{\begin{matrix} (x-10) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x+1)}{9x}\implies \cfrac{x+1}{9x}

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2 years ago
Divide 9x^2 by 18y^2
Neporo4naja [7]

Step-by-step explanation:

√9x2√18y2. √9=3. √x2=x. √18=√9×2=3√2. √y2=y. Therefore √9x2√18y2=3x3√2y = x√2y.

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-(1)=-1<br><br>{True or False}<br><br>Free 40 right here<br><br>​
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True

Step-by-step explanation:

6 0
2 years ago
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75 POINTS Need an immediate answer please brainliest will be given! A train left a station travelling to a city at 30 mph. The t
yaroslaw [1]

The value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.

<h3>What is the rate of speed?</h3>

The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,

r=d/t

Here, (d) is the distance travelled by the object and (t) is time taken but the object to cover that distance.

The train traveled 1/3 of the distance at 30 mph and the remaining distance at 40 mph. Let <em>t</em> is the time the train has taken to travel and x is the distance it travelled. Thus,

t=\dfrac{\dfrac{1}{3}x}{30}+\dfrac{\dfrac{2}{3}x}{40}\\t=\dfrac{x}{90}+\dfrac{x}{60}\\t=\dfrac{2x+3x}{180}\\t=\dfrac{5x}{180}\\t=\dfrac{x}{36}

After two hour a car left the same station traveled the first 3 hours at 35 mph and the remaining distance at 51 mph. Let <em>t</em> is the time the car has taken to travel and x is the distance it travelled. Thus,

t+2=3+\dfrac{(x-3\times35)}{51}

As t is same, thus put the value of t in this equation,

\dfrac{x}{36}=3-2+\dfrac{(x-3\times35)}{51}\\\dfrac{x}{36}=3-2+\dfrac{(x-3\times35)}{51}\\\dfrac{x}{36}=1+\dfrac{(x-105)}{51}\\\dfrac{x}{36}=\dfrac{(51+x-105)}{51}\\51x=36x-54\times36\\51x-36x=1944\\x=\dfrac{1944}{15}\\x=129.6

Thus, the value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.

Learn more about the rate of speed here:

brainly.com/question/359790

#SPJ1

6 0
2 years ago
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