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3 years ago

Can someone please answer. There is one problem. There's a picture thank you!

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

4 0

2 triangles and 3 rectangles.

nignag [31]3 years ago

3 0

2 triangles 3 rectangles.

The first option.

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The side lengths in yards of a triangle and a square are shown in the diagram. The perimeter of the triangle is equal to the per

Tatiana [17]

The value of x given the perimeter of the square is 6.

<h3>What is the value of x?</h3>

The first step is to determine the perimeter of the square.

Perimeter of the square = 4 x length

4 x 2.5x = 10x yards

The perimeter of the triangle is equal to the sum of the three side lengths

2x + 4x - 2 + 2x + 14 = 10x

Combine similar terms

14 - 2 = 10x - 2x - 4x - 2x

Add similar terms

12 = 2x

Divide both sies by 2

x = 6

To learn more about triangles, please check: brainly.com/question/22949981

6 0

2 years ago

Does anyone know how to solve this <br> The answer is B but can anyone explain why

Lana71 [14]

Answer:

B. (0,-1)

Step-by-step explanation:

see.. i'm not rude.... :/

6 0

2 years ago

10p - (3p - 4) = 4(p + 1) + 9

andrezito [222]

Answer:

p = 3

Step-by-step explanation:

distribute parenthesis on both sides of the equation

10p - 3p + 4 = 4p + 4 + 9 ( simplify both sides )

7p + 4 = 4p + 13 ( subtract 4p from both sides )

3p + 4 = 13 ( subtract 4 from both sides )

3p = 9 ( divide both sides by 3 )

p = 3

6 0

3 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

Drag the ordered pair that are 5.5 units apart.

Alexus [3.1K]

Answer:

(-1.5, -3.5) and (-1.5, 2)

Step-by-step explanation:

The x-coordinates in increasing order are ...

-3, -1.5, 5

The distances between pairs of these coordinates are ...

-1.5 -(-3) = 1.5

5 -(-3) = 8

5 -(-1.5) = 6.5

Clearly, any pair with x = 5 is too far away from any pair with a different x-value.

If the distance between pairs is 5.5, then the distance formula tells us the y-coordinate differences for pairs with x-coordinates of -3 and -1.5 must be ...

d = √((x2 -x1)^2 +(y2 -y1)^2)

5.5 = √(1.5^2 +(y2 -y1)^2) . . . substitute known values

30.25 = 2.25 +(y2 -y1)^2 . . . . square both sides

√28 = (y2 -y1) . . . . . . . . . . . . . . subtract 2.25 and take the square root

This value is irrational. Clearly none of the y-coordinates is irrational, so there are no point pairs with x-coordinates -3 and -1.5 that are 5.5 units apart.

If the x-coordinates are the same, then the y-coordinates must differ by 5.5 in order for the points to be 5.5 units apart. The coordinates in order are ...

for x = -1.5, y = -3.5, 2, 2.5 . . . . . differences of 5.5, 6, 0.25

for x = 5, y = -3.5, 1.5 . . . . . . . difference of 5

The only pair we can find that is 5.5 units apart is ...

(-1.5, -3.5) and (-1.5, 2).

6 0

2 years ago