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3 years ago

13

Which statement is true about the value of |6|?

1 answer:

alexdok [17]3 years ago

6 0

What are the options?

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Solve for x in the diagram.<br><br><br><br> A. 25 B. 37 C. 15 D. 14

nirvana33 [79]

Use the Pythagorean theorem for this. (a^2+b^2=c^2)

a=9, b=12, c=x

9^2+12^2=c^2
81 + 144 = c^2
225 = c^2
c =15

the answer is c

4 0

3 years ago

Read 2 more answers

Find the 13th term of a sequence where the

ValentinkaMS [17]

Answer:

First, you write an explicit formula then plug in the value of n in the formula with the term number you are trying to find, in this case the 13th term.

The steps are in the pictures

the final answer is 121 btw

4 0

3 years ago

Please help Which expression is equal to...?

Margarita [4]

Answer:

the last one $-\sqrt{5}$

Step-by-step explanation:

3 0

3 years ago

How many different rectangular prisms can he build if he uses all the cubes

pishuonlain [190]

It depends on how you count them. If you describe them by their dimensions, lowest one first, you can have
1 x 1 x 18
1 x 2 x 9
1 x 3 x 6
2 x 3 x 3

Of course, these dimensions can be put in any order.

8 0

3 years ago

Which number line shows the solution set for |y-9| <12

RUDIKE [14]

Answer:

Option c

$y\geq-3$ or $y \leq 21$

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function $f(x) = |x|$ x> 0 for all real numbers.

Then the inequation:

$|y-9| \leq 12$ has two cases

$(y-9)$ if $y \geq 9$ (i)

$-(y-9)$ if $y < 9$ (ii)

We solve the case (i)

$y \leq 9 + 12\\y\leq21$

We solve the case (ii)

$-y +9 \leq 12\\-y \leq 12-9\\y \geq -3$

Then the solution is:

$y\geq-3$ or $y \leq 21$

8 0

3 years ago