The distance of segment AX sis found to be 8.6 units using the distance formula.
<h3>What exactly is the distance formula?</h3>
- is the distance formula. This works for any two points in two-dimensional space with coordinates (x₁, y₁) for the first and (x₂, y₂) for the second.
- You may easily remember it if you remember that it is Pythagoras' theorem, that the distance is the hypothenuse, and that the coordinate lengths are the difference between the x and y components of the points.
<h3>Why do we employ the distance formula?</h3>
- In complex numbers, the distance formula is used to express the plane and its magnitude.
- Furthermore, distance formulae can be used to calculate the distance between two planes in three-dimensional or n-dimensional planes. It is also used to calculate the magnitude formula.
Given: A(-4, 5), X (1, −2)
We need to find the distance of the segment AX.
Distance of AX is given as :
Therefore, the distance of segment AX sis found to be 8.6 units using the distance formula.
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Step-by-step explanation:
the answer is in the picture
Answer:
280 ft
Step-by-step explanation:
An auditorium is in the shape of an equilateral triangle with side length as 112 ft.
The stage extends from one vertex of the triangle to the mid-segment and the seating area extends from the mid-segment to the rear wall.
*The situation is represented in the attachment.
According to the midpoint theorem, the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.
Hence, the length of the mid-segment in this case is,
Therefore, the perimeter of the seating area is,
Answer: it is 2
Step-by-step explanation: because 7 x 2 is 14
Answer:
y = -5/2 + 14
Step-by-step explanation: