What is the solution to 3/4b=8

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Answer:

$b=\frac{32}{3}$

Step-by-step explanation:

$\frac{3}{4}b=8$

Multiply both sides by 4:

$4\times \frac{3}{4}b=8\times4$

$3b=32$

Divide both sides by 3:

$\frac{3b}{3}=\frac{32}{3}$

$b=\frac{32}{3}$

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If f(z)=m^z - n^z, and f(1)=2, f(2)=8. Find f(3).

Marina CMI [18]

If f(z)=m^z - n^z and f(1)=2, f(2)=8
then
m - n = 2 so m = n + 2
m^2 - n^2 = 8

substitute m = n + 2 into m^2 - n^2 = 8

so
m^2 - n^2 = 8
(n + 2)^2 - n^2 = 8
n^2 + 4n + 4 - n^2 = 8
4n = 4
n = 1

m = n + 2 = 1 + 2 = 3

so f(z) = 3^z - 1^z

if z = 1 the f(1) = 3^1 - 1^1 = 2
if z = 2 the f(2) = 3^2 - 1^2 = 9 - 1 = 8
if z = 3 the f(3) = 3^3 - 1^2 = 27 - 1 = 26

answer
f(3) = 26

3 0

3 years ago

Triangles J K L and X Y Z are shown. Angles K J L and Y X Z are right angles. The length of Y X is 10. The length of hypotenuse

pickupchik [31]

ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

<h3>What are Congruent Triangles?</h3>

Congruent triangles are triangles whose corresponding sides are congruent to each other.

The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.

Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

Learn more about congruent triangles on:

brainly.com/question/11457412