To know if it's even based on it's prime factorization, check to see if it is a multiple of 2. If it is, it is an even number. If it is not, it is an odd number.
x + y = 24 where x and y are the 2 parts of diagonal Other diagonal wil be smaller that 24.
x^2 + z^2 = 13^2
y^2 + z^2 = 20^2 where z = 0.5 * length of smaller diagonal)
form last 2 equations
y^2 - x^2 = 20^2 - 13^2 = 231
now y = 24-x so we have
(24 - x)^2 - x^2 = 231
576 - 48x = 231
48x = 345
x = 7.1875
z^2 = 13^2 - 7.1875^2 = 117.34
z = 1.83
so smaller diagonal = 21.66 cm
looks like its the third choice.
Answer:
3 times more.
Step-by-step explanation:
The odds of landing a dart in any of the circles correspond to the surface area of the circle.
Calculate the surface area of both circles:
The formula for the area of a circle is
.
- inner circle:

- for the outer circle, use the formula then subtract the value of the inner circle, to find the remaining area:

Calculating greater chance:
Divide the larger area by the smaller area:

That means that the area of the outer circle is 3 times larger, making it 3 times more likely to hit the outer circle. Therefore the points for hitting the inner circle should be 3 times more.
The answer to the problem is as follows:
We can convert 4.5% into a decimal form by moving the decimal to the left two places. This becomes: .045
<span>63.20 x .045 = $2.84
</span>I hope my answer has come to your help. God bless and have a nice day ahead!
The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.
Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.
On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057