(1.) 35-3m
m= 4
35-3m
= 35-3(4)
= 35-12 (do the multiple/division first before doing the addition/subtraction)
= 23
C. 23
(2.) 1 + x ÷ 5
x = 80
1 + x ÷ 5
= 1+80÷5
= 1+16
= 17
(3.) mx-y
m=5, x=3, and y=8
mx-y
= 5(3)-8
= 15-8
= 7
(4.) 3a+15+bc−6
a=7, b=3, and c=15
3a+15+bc-6
= 3(7)+15+3(15)-6
= 21+15+45-6
= 75
Answer:
48
Step-by-step explanation:
x = -2 y =3
3x² - 2xy²
3(-2)² -2(-2)(3)²
square first
3*4 -2(-2)*9
multiplty from left to right
12-2(-2)*9
multiply from left to right again
12 -(-36) subtract using rule for integers that double minus is plus
12 + 36
48
Recall your d = rt, distance = rate * time
so, keeping in mind that both trains are going at the same speed, say speed of "r" mph, after 212 hours A arrived at station A and after 4 hours, B arrived at station B.
now, the distance covered by train A is say "d", we know both stations are 585 miles apart, so, if train A covered "d" miles in those 212 hours, then train B covered the slack from 585 and d, that is "585 - d".
1.) 5
2.) 13
3.) -350
4.) 150
5.) -520
6.) 200
7.) 5
8.) -9
9.) -3
10.) 13
hope this helped