2 years ago

Given sinx= −3/5 when 3π/2 < x < 2π, find tan x/2

Mathematics

2 answers:

olasank [31]2 years ago

7 0

sinx = -3/5

Adjacent² = 5² - 3² = 16

Adjacent = 4

tan(x) = -3/4

-¾ = 2tan(½x)/[1 - tan²(½x)]

-3 + 3tan²(½x) = 8tan(½x)

3tan²(½x) - 8tan(½x) - 3 = 0

tan(½x) = 3, -⅓

Hope it helps you

GarryVolchara [31]2 years ago

5 0

Answer:

B -⅓

Step-by-step explanation:

sinx = -3/5

Adjacent² = 5² - 3² = 16

Adjacent = 4

tan(x) = -3/4

-¾ = 2tan(½x)/[1 - tan²(½x)]

-3 + 3tan²(½x) = 8tan(½x)

3tan²(½x) - 8tan(½x) - 3 = 0

tan(½x) = 3, -⅓

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