Question

A wastewater treatment plant receives 20million gallons per day (mgd) of flow. This wastewater has a solid concentration of 384mg solids/L. How many pounds of solids enter the plant each day

Answer 1

Answer:

64,092.73 pounds

Step-by-step explanation:

1 gallon = 3.78541 liter

1 pound = 453592 mg

In order to obtain the weight of solids that enter the plant each day, simply multiply the wastewater flow by the solids concentration and make the necessary unit adjustments:

$W=20,000,000\ gal*384\frac{mg}{L}*\frac{3.78541\ L}{1\ gal}*\frac{1\ lbs}{453592\ mg} \\W=64,092.73\ lbs$

64,092.73 pounds of solids enter the plant each day.