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2 years ago

How do you solve a=a+b+c/3

Mathematics

1 answer:

Mrac [35]2 years ago

3 0

I hope this helps you

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Evalue f(x)=(-2)^2-3(-2)+5/(-2)^2+1

Nina [5.8K]

F(x)=4+6+5/4+1
F(x)=4+6+5/5
F(x)=10+1=11

Answer =11

8 0

3 years ago

Someone please help!! ASAP

prohojiy [21]

Answer:

x=−5 and y=1

Step-by-step explanation:

7 0

3 years ago

Find the value of x, o is the centroid

Ray Of Light [21]

Answer:

x = 14

Step-by-step explanation:

In the triangle O is the centroid.

Now, we know that the centroid divides the medians in the 2 : 1 ratio that means the distance from the centroid to the vertex and the distance from the centroid to the opposite side remains in 2 : 1 ratio.

So, from the given diagram we can write

$\frac{3x}{2x - 7} = \frac{2}{1}$

⇒ 3x = 4x - 14

⇒ x = 14 (Answer)

3 0

3 years ago

Is the perimeter of a square and its side length linear or not linear?

NARA [144]

Its linear , if side is x then perimeter is 4x
I hope this helps, if you have any further questions don't hesitate to ask

4 0

3 years ago

What is the solution to the following equation? x2 + 3x + 4 = 0

andreev551 [17]

Answer:

$x=\dfrac{-3\pm \sqrt7i}{2}$

Step-by-step explanation:

The given equation is $x^{2}+3x+4=0$ .

We need to find the solution of the above equation.

The solution of an equation $ax^2+bx+c=0$ is :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

We have, a = 1, b = 3 and c = 4

$x=\dfrac{-3+ \sqrt{(3)^2-4(1)(4)} }{2}, \dfrac{-3- \sqrt{(3)^2-4(1)(4)} }{2}\\\\=\dfrac{-3+\sqrt{9-16}}{2}, \dfrac{-3-\sqrt{9-16}}{2}\\\\=\dfrac{-3\pm \sqrt7i}{2}$

So, the solution of the given equation is $\dfrac{-3\pm \sqrt7i}{2}$ .

5 0

3 years ago