The box and whisker plots represent the number of minutes spent by users on two different social media groups. Which THREE state
ments are correct when comparing the plots?
A) The median time for users of Group B is 40 minutes.
B) Group B has greater median value than Group A.
C) The data for Group B varies slightly more than Group A.
D) The spread of the data for Group A is 25 minutes.
E) The spread of the data for Group A is 40 minutes. 
A) The median time for users of Group B is 40 minutes.
B) Group B has greater median value than Group A.
C) The data for Group B varies slightly more than Group A.
D) The spread of the data for Group A is 25 minutes.
E) The spread of the data for Group A is 40 minutes.
2 answers:
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Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
= # of adults attended
700-633 = c = 66 
= # of children attended
$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
700-633