Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
D
Step-by-step explanation:
use the order of operations for this equation.
multiplication comes first.
11(11) - 6(17) + 4
121 - 102 + 4
for addition and subtraction, order doesn’t matter.
121 - 102 = 19
19 + 4 = 23
answer = 23
Answer:
- The correct equation is 6s = 7.80
- The solution of the equation is s = $1.30
Step-by-step explanation:
To find the product of 6 and a number, first we denote the unknown number as s.
The product of 6 and s is the same as 6s.
If the product of both numbers is $7.80, then 6s = $7.80
The correct equation is therefore 6s = $7.80
To get the value of s, we will divide both sides by 6 to have:
6s/6 = $7.80/6
s = $1.30
Based on the calculation, the following statements are true
- The correct equation is 6s = 7.80
- The solution of the equation is s = $1.30
I hope this helps you
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