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3 years ago

What is the value of 4x^3 + 4x when X=4?

Mathematics

1 answer:

IRISSAK [1]3 years ago

5 0

Step-by-step explanation:

$4 {x}^{3} + 4x \\ = 4 \times ( {4})^{3} + 4 \times 4 \\ = 4 \times 64 + 16 \\ = 256 + 16 \\ = 272$

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Evaluate the function below for x = 2.<br>f (x) = 4x^3 - x^2 - 5x+7<br>

nexus9112 [7]

Answer: $f(2)=25$

Step-by-step explanation:

You know that the given function is:

$f(x)=4x^3-x^2-5x+7$

You know that you must evaluate this function for $x=2$ .

Then, to evaluate the function for $x=2$ , you need to substitute this value into the given function and simplify it.

Therefore, you get:

$f(x)=4x^3-x^2-5x+7\\f(2)=4(2)^3-(2)^2-5(2)+7\\f(2)=4(8)-(4)-10+7\\f(2)=32-4-10+7\\f(2)=25$

So, the answer is: $f(2)=25$

8 0

3 years ago

Rewrite the logarithm as an exponential equation: <br> In(X)= 7

Leto [7]

Answer:

$e^7=x$

Step-by-step explanation:

Given the logarithm function

$In\left(x\right)=\:7$

For logarithmic equations, $\log _b\left(x\right)=y$ is equivalent to $b^y=x$ such that

$x>0\:,\:b>0$ and $b\ne 1$

In current case:

$b=e\:$

$\:x=x$

$\:y=7$

Substituting the values of $b\:,\:x\:$ and $y$ into the equation $b^y=x$

$e^7=x$

4 0

4 years ago

Six teammates are competing for first, second, and third place in a race.

Olegator [25]

Answer:

Therefore, There are 120 possibilities for the top three positions

Step-by-step explanation:

Given that : Six teammates are competing for first, second, and third place in a race.

Total number of teammates in the team = 6

Total number of positions offered for winning in the competition = 3 ( first, second, and third place)

Now, we need to find the number of possibilities for the top three positions

Possibility for 1st position = 6

Possibility for 2nd position = 5

Possibility for 3rd position = 4

$\text{So,Total number of possibilities = }6\times 5\times 4=120$

Therefore, There are 120 possibilities for the top three positions

3 0

3 years ago

Read 2 more answers

What would the total account value be if i deposited 14,000 into a bank account earning 3.25% compounded quarterly for 4 years?

LUCKY_DIMON [66]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$14000\\
r=rate\to 3.25\%\to \frac{3.25}{100}\to &0.0325\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=14000\left(1+\frac{0.0325}{4}\right)^{4\cdot 4}\implies A=14000(1.008125)^{16}$

7 0

3 years ago

What is 2³ I need a example

Sav [38]

Answer: 8

Step-by-step explanation: That digit above the 2 is a exponent. It represents the number of times 2 is multiplying itself. This is simply 2x2x2. 2x2x2=4x2=8

4 0

4 years ago