Answer:
{0, 1, 2, 3, 4} --> 96 5-digit numbers possible with this set.
Step-by-step explanation:
i dunno, i kinda just searched it up
link: https://gmatclub.com/forum/how-many-five-digit-numbers-can-be-formed-using-digits-91597.html#:~:text=If%200%20is%20included%3A,numbers%20possible%20with%20this%20set.
(b) To have no winner within the first 6 tosses means that there must be 3 tails and 3 heads tossed. So we count how many ways can that happen. The number of ways to choose 3 heads (or tails, doesn't matter) from 6 tosses is

so 20 ways winthin the 6 tosses. but the question was "how many ways among the 128 of 7 tosses" so we need to add the 7th toss by multiplying by another 2 possibilities for the outcome of the 7th toss, giving us the answer: among the 128 there are 40 games that are tied and need the 7th toss.
(c) The probability is the number of tied games (after 6 tosses) divided by the total number of possible configurations among 6 tosses:

Answer:
r - 5 = 2c
r = 75
Step-by-step explanation:
To write an equation for the problem, we first need do declare the value of the number of apps cora has.
Let c = Cora's apps
r - 5 = 2c
r - 5 is used to indicate that Rita deleted 5 apps.
2c is used to represent the twice the number of apps Cora has.
Now you said that Cora had 35 apps.
Let's plug that into the equation.
r - 5 = 2c
r - 5 = 2(35)
r - 5 = 70
Now we transpose the -5 to the other side to leave r.
r = 70 + 5
r = 75
So if Cora has 35 apps, then Rita will have 75 apps.