Microsoft Excel Module 6

Convert the following hexadecimal numbers to decimal: (a) FF (b) F0A2 (c) 0F100 (d) 100

Hatshy [7]

Answer:

a) 255

b) 61602

c)

d)

Explanation:

You need to understand the decimal equivalent of hexadecimal numbers, from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.

For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:

a. F F

position 1 0

Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:

$F*16^{0}=15*1=15\\F*16^{1}=15*16=240$

Finally, you'll add your results:

240+15=255

FF=255

b. F 0 A 2

position 3 2 1 0

$2*16^{0}=2*1=2\\A*16^{1}=10*16=160\\0*16^{2}=0*256=0\\F*16^{3}=16*4096=61440\\\\2+160+0+61440=61602\\$

F0A2=61602

c. F 1 0 0

position 3 2 1 0

$0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\F*16^{3}=16*4096=61440\\0+0+256+61440=61696\\$

0F100=61696

d. 1 0 0

position 2 1 0

$0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\\\0+0+256=256\\$

100=256

I hope you find this information useful! Good luck!

8 0

3 years ago

If a fire should break out in your building, which of the following actions is NOT recommended?

quester [9]

C) Scream and run

you need to remain calm and carefully exit the building making sure you have everybody with you

6 0

3 years ago

Read 2 more answers

How did voyager 1 and voyager 2 made outer space exploration and easier

Anna007 [38]

They made it easier because they mapped out some of the galaxy and hazardous things like Astroid belts or rogue planets

5 0

3 years ago

Under which of the following conditions will evaluating this boolean expression

zzz [600]

1.)
((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) 

The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. 

For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. 

a.) (i <= n) || (i >= n) 

This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. 

b.) (a[i] == 0) && (a[i-1] == 0) 

This means that both of these terms are true. We substitute. 

((i <= n) && true) || (((i >= n) && true)) 

Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: 

(i <= n) || (i >= n) 

This is clearly always true.

3 0

3 years ago

Write a function listLengthOfAllWords which takes in an array of words (strings), and returns an array of numbers representing t

vesna_86 [32]

Answer:

public static int[] listLengthOfAllWords(String [] wordArray){

int[] intArray = new int[wordArray.length];

for (int i=0; i<intArray.length; i++){

int lenOfWord = wordArray[i].length();

intArray[i]=lenOfWord;

}

return intArray;

}

Explanation:

Declare the method to return an array of ints and accept an array of string as a parameter
within the method declare an array of integers with same length as the string array received as a parameter.
Iterate using for loop over the array of string and extract the length of each word using this statement int lenOfWord = wordArray[i].length();
Assign the length of each word in the String array to the new Integer array with this statement intArray[i]=lenOfWord;
Return the Integer Array

A Complete Java program with a call to the method is given below

import java.util.Arrays;

import java.util.Scanner;

public class ANot {

public static void main(String[] args) {

String []wordArray = {"John", "James", "David", "Peter", "Davidson"};

System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));

}

public static int[] listLengthOfAllWords(String [] wordArray){

int[] intArray = new int[wordArray.length];

for (int i=0; i<wordArray.length; i++){

int lenOfWord = wordArray[i].length();

intArray[i]=lenOfWord;

}

return intArray;

}

}

This program gives the following array as output: [4, 5, 5, 5, 8]

7 0

3 years ago