How long before a speech should you begin practicing?

a. Fill in the blanks with suitable words: A software that controls and manages all the activities of the computer ... b. A soft

zavuch27 [327]

Explanation:

i don't know

4 0

3 years ago

Which statement best describes the difference between a spreadsheet and a database?

Dmitrij [34]

Answer:

Databases store data in tables that interact; spreadsheets store data in cells that interact.

Explanation:

3 0

2 years ago

Read 2 more answers

Write a function called countstuff () that takes as a parameter a character array, and returns an int. The prototype must be:

PSYCHO15rus [73]

Answer:

Please kindly go to the explanation part.

Explanation:

The required function is written in Raw code below.

Function:

#include<stdio.h>

#include<ctype.h> //including required libraries

int countstuff(char s[]){ //Function countstuff

int cntUp=0,cntLow =0,cntDigits = 0,i=0,value; //declaring required variables

for(i=0;s[i]!='\0';i++){ //loop to iterate over the characters of string

if(isupper(s[i])){

cntUp++; //incrementing count of uppercase if it is uppercase character

}

else if(islower(s[i])){

cntLow++; //incrementing count of lowercase if it is lowercase character

}

else if(isdigit(s[i])){

cntDigits++; //incrementing count of digits if it is digit

}

value = cntUp*1000000 + cntLow*1000 + cntDigits; //counting value using formula given in question

return value; //returning the value

}

void main(){

char string[1000]; //declaring required variables

int value;

printf("Enter a String:");

scanf("%[^\n]s",string); //taking string as input

value = countstuff(string); //calling function

printf("The Value is : %d\n",value); //printing result

}

5 0

3 years ago

Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3

Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0

3 years ago

Leo lives in a two-story home in an upscale neighborhood, drives a brand-new sports car, and makes more than $250,000 per year.

prisoha [69]

(D) Standard of living. Because, from this text you can tell that Leo is a wealthy person, and welthy people tend to get the best things, including fancy neighborhoods and Cars. So its most likely (D)

5 0

3 years ago

Read 2 more answers