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3 years ago

Please help I’m in a hurry my class is in 26 minutes!

Mathematics

1 answer:

fenix001 [56]3 years ago

4 0

Answer:

by SAS congruence rule

Step-by-step explanation:

WX=ZY (given) (side)

angle X =angle Z (given) (angle)

XZ=XZ. (common side) (side)

the picture isnt that clear but i hope that this is right..

hope this helps u :)

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PLEASE EXPLAIN AND HELP WILL MARK BRAINLIEST

vagabundo [1.1K]

Answer:

I dunno this one, u should

Step-by-step explanation:

5 0

3 years ago

Ann's first option is a plot of land adjacent to a current park.

oksian1 [2.3K]

Given:

The equation for the area of the first option is:

$x^2+200x=166400$

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

$x^2+200x=166400$

It can be written as:

$x^2+200x-166400=0$

Splitting the middle term, we get

$x^2+520x-320x-166400=0$

$x(x+520)-320(x+520)=0$

$(x-320)(x+520)=0$

$x=320,-520$

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0

3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

4 years ago

A surveyor is calculating the width of a canyon. He has taken the measurements shown below. What is the width of the canyon? Typ

Serga [27]

Answer:

480 ft

Step-by-step explanation:

To find the width (x), apply the similarity theorem of two similar triangles, which says that the corresponding lengths of two similar triangles are proportional.

Thus:

x/72 = 80/12

Cross multiply

12 × x = 80 × 72

12x = 5,760

12x/12 = 5,760/12

x = 480

Width of the canyon = x = 480 ft

8 0

3 years ago