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Eddi Din [679]
2 years ago
12

Find the area of the figure 3m 6m 8m A.48m B.36m C.24m D.60m

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
3 0

Answer:

B. 36 square meters

Step-by-step explanation:

Find the areas of the rectangle and triangle. Then, subtract the area of the triangle from the area of the rectangle to get the area of only the figure.

rectangle A = 8(6) = 48 square meters

triangle A = 1/2(8)(3) = 12 square meters

48 - 12 = 36 square meters

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Answer:

x = -6

Step-by-step explanation:

-2 = 12/x

-2x = 12

x = 12/-2

x = -6

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3 years ago
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Tyra wants to arrange 32 tiles in equal rows and columns. how many ways could she organized the tiles? list the factors
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I did this in school!!
You can do it 4 times.
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What is the answer to this 8x+14y=4<br> -6x-7y=-10
cestrela7 [59]

Answer:

14x=4-21y

Step-by-step explanation:

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3 years ago
The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
aniked [119]

Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0
3 years ago
What type of graph organizes data into 4 groups of equal size, and is often used to compare two sets of data.
aliina [53]

The plot that organizes the data into 4 groups of equal sizes is box and whisker plot.

The image below shows a box and whisker plot. Following are the elements of box and whisker plot:

Minimum = This is the smallest value of the data set

Q1 = First (Lower) Quartile of the data set. 25% of the data values lie below this point

Q2 = Second Quartile or Median. This is the central value so 50% of the data values lie below this point

Q3 = Third (Upper) Quartile of the data set. 75% of the data values lie below this point.

Maximum = This is the maximum value of the data set.

Based on box and whisker plot we can compare two or more sets of data by comparing the spread of the data. We can also directly observe from the box and whisker plot if the data is uniform, normal or skewed. Using box and whisker plot we can also visualize any outliers that may be in the data.

8 0
3 years ago
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