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ddd [48]
2 years ago
8

Ratio 5: 12 if there are 50 trucks how many cars are there​

Mathematics
1 answer:
dexar [7]2 years ago
5 0

If the 50 trucks represent the 5 in the ratio 5:12, then there are 120 cars.

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HELP ASAP. please show work tysm! solve for x
nata0808 [166]

Answer:

71

Step-by-step explanation:

vertical sides  are congruent

x+30=101

x=71

7 0
2 years ago
1,write the successor of-5 and predecessor of 6 then add them
Alona [7]

#1

  • Successor of -5=-4
  • Predecessor of 6=5

\\ \tt\hookrightarrow -4+5=1

#2

  • Let one be x and other be x-1

\\ \tt\hookrightarrow a-b=x-x+1=+1

#3

\\ \tt\hookrightarrow 42-66-(100-24)

\\ \tt\hookrightarrow -24-76

\\ \tt\hookrightarrow -100

3 0
2 years ago
Read 2 more answers
What is the domain of this graph?
jolli1 [7]

Answer:

B 0 ≤x≤9

Step-by-step explanation:

The domain is the input values of the graph.  In this graph it is the values that the time variable takes.

Time can take 0 seconds to 9 seconds

0 ≤x≤9

8 0
3 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
Find the unknown length x in the right triangle, to the nearest tenth .
VARVARA [1.3K]

Answer:

x = 11.7

Step-by-step explanation:

sin of an angle is opposite/hypotenuse

sin 38 = x/19

x = 19 sin 38

x = 11.7

You need to memorize the definitions of all the trig functions and then this type of problem will be easy for you.

8 0
2 years ago
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