Which expression is equivalent to -5 7/8?

Mathematics

1 answer:

Bond [772]3 years ago

6 0

Answer:

The answer is b) -5+ -7/8

Step-by-step explanation:

It is this answer because remember a negative plus a negative equals a negative, so when you add the too negative numbers together you get a negative answer.

EXAMPLE:

5 + 7/8 = 5 7/8

-5 + -7/8= -5 7/8

I'm positive it is correct

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A company rents out 11 food booths and 22 game booths at the county fair. The fee for a food booth is $125 plus $6 per day. The

sattari [20]

Answer:

$3135 + $286d

Step-by-step explanation:

Given that:

Food booth = 11

Game booth = 22

Let number of days = d

Food booth rent = ($125 + 6d) * 11

Game booth rent = ($80 + 10d) * 22

Food booth = $1375 + $66d

Game booth = $1760 + $220d

Amount company is paid :

Food booth rent + game booth rent

($1375 + $66d) + ($1760 + $220d)

$(1375 + 1760) + $(66d + 220d)

$3135 + $286d

8 0

3 years ago

Complete the table by converting each decimal to a fraction.

AlekseyPX

if you've read those links already, you'd know what we're doing here.

we'll move the repeating part to the left-side of the dot, by multiplying by "1" and as many zeros as needed, or 10 at some power pretty much.

on 0.13 we need 100 to get 13.13.... and on 0.1234, we need 10000 to get 1234.1234....

$\bf 0.\overline{13}~\hspace{10em}x=0.\overline{13}
\\\\[-0.35em]
~\dotfill\\\\
\begin{array}{|lll|ll}
\cline{1-3}
&&\\
100\cdot 0.\overline{13}& = & 13.\overline{13}\\
100\cdot x&& 13 + 0.\overline{13}\\
100x&&13+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
100x=13+x\implies 99x=13
\\\\
x=\cfrac{13}{99}
\end{array}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
0.\overline{1234}~\hspace{10em}x=0.\overline{1234}
\\\\[-0.35em]
~\dotfill$

$\bf \begin{array}{|ccc|ll}
\cline{1-3}
&&\\
10000\cdot 0.\overline{1234}&=&1234.\overline{1234}\\
10000\cdot x&=&1234+0.\overline{1234}\\
10000x&=&1234+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
10000x=1234+x
\\\\
9999x=1234\implies x=\cfrac{1234}{9999}
\end{array}$