What is .825252525 repeating as a fraction

1 answer:

5 0

Let d = 0.825252525..., then
$10d = 8.25252525...=8\frac{25}{10^2-1}=8\frac{25}{99}$

Therefore,
$d=\frac{8}{10}+\frac{25}{990}=\frac{8(99)+25}{990}=\frac{817}{990}$

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What is the length of DE?

miskamm [114]

Answer:

Step-by-step explanation:

If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.

AC *CB = CD CE

4 * (10-4) = CD * 8

4 * 6 = 8 *CD

24 = 8 CD

Divide each side by 8

24/8 = CD

3 = CD

We want the length DE

DE = CD + CE

= 3 + 8

DE = 11

5 0

3 years ago

Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 4,000,000 and a mean

In-s [12.5K]

Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 19000, \sigma = \sqrt{4000000} = 2000$

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20179 - 19000}{2000}$