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Svetllana [295]
3 years ago
9

T²= 4π² (M+m) ÷ ug

Mathematics
1 answer:
inessss [21]3 years ago
6 0

Starting with ...

T^2=\dfrac{4\pi^2(M+m)}{ug}

1) Multiply by the inverse of the coefficient multiplying the sum with M, then subtract m.

\dfrac{T^2ug}{4\pi^2}=M+m\\\\M=\dfrac{T^2ug}{4\pi^2}-m

2) Multiply by g/T²

g=\dfrac{4\pi^2(M+m)}{T^2u}

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