All categories

3 years ago

T²= 4π² (M+m) ÷ ug

Mathematics

1 answer:

inessss [21]3 years ago

6 0

Starting with ...

$T^2=\dfrac{4\pi^2(M+m)}{ug}$

1) Multiply by the inverse of the coefficient multiplying the sum with M, then subtract m.

$\dfrac{T^2ug}{4\pi^2}=M+m\\\\M=\dfrac{T^2ug}{4\pi^2}-m$

2) Multiply by g/T²

$g=\dfrac{4\pi^2(M+m)}{T^2u}$

You might be interested in

5x * 2y<br><br> Please help<br> ASAP

DedPeter [7]

<h2>ANSWER:</h2>

10xy

<h2>Explanation:</h2>

We know that 5*2 is equal to 10:

$5*2=10\\$

You know that x*y will become xy:

$x*y=xy$

Therefore, the answer would be 10xy: $5x*2y=10xy$

Hope this helps!

7 0

3 years ago

Read 2 more answers

Factor completely<br> 3x^2 + 7x - 6 <br><br><br> Zzz

Dmitrij [34]

Answer:

(3x−2)(x+3)

Step-by-step explanation:

these are ur answers

8 0

3 years ago

Read 2 more answers

I don’t know where to start with this problem

elixir [45]

Answer:

√(4/5)

Step-by-step explanation:

First, let's use reflection property to find tan θ.

tan(-θ) = 1/2

-tan θ = 1/2

tan θ = -1/2

Since tan θ < 0 and sec θ > 0, θ must be in the fourth quadrant.

Now let's look at the problem we need to solve:

sin(5π/2 + θ)

Use angle sum formula:

sin(5π/2) cos θ + sin θ cos(5π/2)

Sine and cosine have periods of 2π, so:

sin(π/2) cos θ + sin θ cos(π/2)

Evaluate:

(1) cos θ + sin θ (0)

cos θ

We need to write this in terms of tan θ. We can use Pythagorean identity:

1 + tan² θ = sec² θ

1 + tan² θ = (1 / cos θ)²

±√(1 + tan² θ) = 1 / cos θ

cos θ = ±1 / √(1 + tan² θ)

Plugging in:

cos θ = ±1 / √(1 + (-1/2)²)

cos θ = ±1 / √(1 + 1/4)

cos θ = ±1 / √(5/4)

cos θ = ±√(4/5)

Since θ is in the fourth quadrant, cos θ > 0. So:

cos θ = √(4/5)

Or, written in proper form:

cos θ = (2√5) / 5

4 0

3 years ago

II'll mark brainliest who is the first to answer both questions correctly.

Strike441 [17]

Answer:

A) The probability that each player gets an ace, a 2 and a 3 with the order unimportant = (72/1925) = 0.0374

B) The probability of winning the jackpot = (1/1200) = 0.0008333

Step-by-step explanation:

A) There are four Aces, four 2's, and four 3's, forming a set of 12 cards

These cards are to be divided at random between 4 players.

What is the probability that each player gets an ace, a 2 and a 3.

We start with the first player, the probability of these cards for the first player, with order not important (because order isn't important, there are 6 different arrangement of the 3 cards)

6 × (4/12) × (4/11) × (4/10) = (16/55)

Then the second player getting that same order of cards

6 × (3/9) × (3/8) × (3/7) = (9/28)

Third player

6 × (2/6) × (2/5) × (2/4) = (2/5)

Fourth player

6 × (1/3) × (1/2) × (1/1) = 1

Probability that each of the players get different cards is then a multiple of the probabilities obtained above

= (16/55) × (9/28) × (2/5) × 1

= (288/7700) = (72/1925) = 0.0374

B) The concluding part of the B question.

To win the jackpot, the numbers on your ticket must match the three white balls and the SuperBall. (You don't need to match the white balls in order). If you buy a ticket, what is your probability of winning the jackpot?

Probability of wimning the jackpot is a product the probability of getting the 3 white balls correctly (order unimportant) and the probability of picking the right red superball

Probability of picking 3 white balls from 10

First slot, any of the 3 lucky numbers can fill this slot, (3/10)

Second slot, only 2 remaining lucky numbers can fill this slot, (2/9)

Third slot, only 1 remaining lucky number can fill this slot, (1/8)

(3/10) × (2/9) × (1/8) = (1/120)

Probability of picking the right red superball

(1/10)

Probability of winning the jackpot = (1/120) × (1/10) = (1/120) × (1/10) = (1/1200) = 0.0008333

Hope this Helps!!!

5 0

3 years ago

Merry Christmas Eve Eve everyone! i can't wait to celebrate the birth of Jesus Christ! i appreciate Jesus Christ dying on the cr

Sidana [21]

I know I’m late but

WOOOOOOOOOOOOOOOOO JESUS!!!

Can’t wait for next year Haha!!!

3 0

3 years ago