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Oksanka [162]
4 years ago
15

Think about a carbon atom that is released into the atmosphere from burning wood in a campfire. If it were to go through the who

le carbon cycle, number the steps that would follow.1.
step 1

step 2

step 3

step 4

step 5

a. The bird decomposes and the carbon returns to the atmosphere.

b. A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis.

c. A caterpillar gets the carbon by eating the tree's leaves.

d. The bird flies into a building and dies instantly. It falls to the ground.

e. A bird gets the carbon by eating the caterpillar.
Biology
1 answer:
Vera_Pavlovna [14]4 years ago
4 0

Step 1 is B ,2 is c, 3 is e, 4 is d, 5 is a

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Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

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           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

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Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

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4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

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b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

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