Answer:
measure of other diagonal is 30cm
Step-by-step explanation:
let the other diagonal be d .
- area of rhombus = 1/2 × 16 × d
- 240 = 8 × d
- d = 240 / 8
- d = 30
hence the other diagonal = d = 30 cm
Slope (m) of a line = (y2-y1)/(x2-x1)
So for line AB, the slope is (3-2)/(-1-1)
= 1/-2 = -1/2
For line AC = (3--1)/(-1--3) = (3+1)/(3-1)
= 4/2 = 2
For line BC = (2--1)/(1--3) = (2+1)/(1+3)
= 3/4
In order for an angle (<) to be right, it must be 90°, so the two lines making the right angle must be perpendicular. Perpendicular lines by definition have slopes that are the negative reciprocal. That means that you change the sign of one line's slope (m) and divide 1 by it:
m2 = 1/-m1
So for lines AB and AC: m(AC) = 1/-m(AB),
does 2 = 1/--1/2? YES!! 1/--1/2 = 1/1/2 = 2, so < BAC is 90° and therefore a right <
How about for lines AB and BC: m(BC) = 1/-m(AB), does 3/4 = 1/--1/2? NO, because 1/--1/2 = 1/1/2 = 2, not = to 3/4, so < ABC is not right
How about our last < BCA: m(AC) = 1/-m(BC), does 2 = 1/-3/4? NO, because 1/-3/4 = -4/3, not = to 2, so < BCA is not right
So yes, the triangle is a right triangle because < BAC is right (=90°)!
Answer: For altitudes up to 36,000 feet, the relationship between temperature and altitude can be described by the formula t=-0.0035a+g, where t is the temperature in degrees Fahrenheit, a is the altitude in feet, and g is the ground temperature in degrees Fahrenheit. Solve this formula for a.
Step-by-step explanation:For altitudes up to 36,000 feet, the relationship between temperature and altitude can be described by the formula t=-0.0035a+g, where t is the temperature in degrees Fahrenheit, a is the altitude in feet, and g is the ground temperature in degrees Fahrenheit. Solve this formula for a.
X+3. Al you have to do when it’s more is add, when it’s less subtract
Answer:
5
Step-by-step explanation:
When you are dividing fractions you must flip the second digit and the sign should be changed to multiplication sign.
So in this equation it will be
2 / 4/10 =
2 * 10/4=
20/4=
5
Hope you found this answer helpful
