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tensa zangetsu [6.8K]
3 years ago
9

A local grocery story has strawberries on sale for $1.45 per pound. How much would it cost to buy 5.5 pounds of strawberries? Ro

und your answer to the nearest penny. Show your work on the sketchpad and type your answer below
Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

Answer: The cost of 5.5 pounds strawberries =$ 7.98

Step-by-step explanation:

Given: A local grocery story has strawberries on sale for $1.45 per pound.

i.e. Cost for 1 pound strawberries = $1.45

Now, Cost of 5.5 pounds strawberries =  5.5 x (Cost for 1 pound strawberries)

= $ (5.5 x  1.45)

= $ 7.975 ≈ $ 7.98   [ Round to the nearest penny]

Hence, the cost of 5.5 pounds strawberries =$ 7.98

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Jet001 [13]

Step-by-step explanation:

D. Both charges must be different.

Because, like charges repel each other and different charges attract each other.

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4 years ago
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In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

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3 years ago
What is the decibel level of the noise from a fire alarm with intensity 10^-1 watts per square inch
prisoha [69]

Answer:

110 db

Step-by-step explanation:

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3 years ago
The slope of the line below is 2. Which of the following is the the point-slope form of the line?
Jobisdone [24]

Answer:  y + 1 = 2 (x -1)

Step-by-step explanation:

Point slope form is:

y - y1 = m (x - x1)

Point on the line is (1, -1) and slope is 2

m = 2

y1 = -1

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y - (-1) = 2 (x - 1) or y + 1 = 2 (x -1)

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3 years ago
What are the points if the slope is 4 and the point is (1,-1)
kherson [118]

The points if the slope is 4 and the point is (1,-1) are (1,-1) and (2, 3)

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the points?</h3>

The given parameters are:

Slope = 4

Point = (1, -1)

The slope of 4 means that as x changes by 1, the value of y changes by 4

This means that, we have:

(x + 1, y + 4)

Substitute the known values in the above equation

(1 + 1, -1 + 4)

Evaluate

(2, 3)

Hence, the points if the slope is 4 and the point is (1,-1) are (1,-1) and (2, 3)

Read more about linear equations at:

brainly.com/question/14323743

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