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2 years ago

A circle has a radius of 12. What is the diameter?

Mathematics

2 answers:

AveGali [126]2 years ago

7 0

Answer:

24.

Step-by-step explanation:

the diameter is twice the radius

dimulka [17.4K]2 years ago

7 0

Answer:

Step-by-step explanation:

because radius=1/2 of diameter

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Math question

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

3 years ago

W=zr-2zt^3 solve for z

ladessa [460]

Answer: z=0

Step-by-step explanation:

W=zr-2zt^3

Move all terms containing z to the left, all other terms to the right.

dd '-1rz' to each side of the equation.

-1rz+z=rz+-1rz+-2t^3z

Combine like terms: rz + -1rz = 0

-1rz+z=0+(-2t^3z)

-1rz+z=-2t^3z

Add 2t^3z to each side

-1rz+2t^3z+z=-2t^3z+2t^3z

Combine the like terms 2t^3z+2t^3z=0

-1rz+2t^3z+z=0

Factor out the Greatest Common Factor (GCF), 'z'.

z(-1r+2t^3+1)=0

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

8 0

3 years ago

Which of the follow tables do not show a linear function

valina [46]

C , i dont know if it’s right but it’s the only table with the same number on the bottom . and same number in general

6 0

3 years ago

Read 2 more answers

Please help!!!! I'm terrible at algebra and I need your help!!!

noname [10]

It will be the third one

5 0

3 years ago

Solve the system by the elimination method <br> 7x+5y=-25<br> 5x+3y=-23

aksik [14]

Step-by-step explanation:

7x+5y=25 ×3 7×-1.5+5y=25

5x+3y= -23 ×5 -10.5 +5y =25

5y= 25 + 10.5

21x+15y=75 5y= 35.5

25x+15y=69 y= 7.1

-4x=6

x=-1.5

5 0

3 years ago