Answer:
x = -5/2 y +25/2
Step-by-step explanation:
5y + 2x = 25
Subtract 5y from each side
5y + 2x -5y= -5y+25
2x = -5y +25
Divide by 2
2x/2 = -5y/2 +25/2
x = -5/2 y +25/2
Answer: B)
Corresponding parts must be in the same position.
Step-by-step explanation:
Answer:
The correct option is B.
Step-by-step explanation:
The given function is

The translation of a function is defined as

If a>0, then the graph of f(x) shift a units left and if a<0, then the graph of f(x) shift a units right.
If b>0, then the graph of f(x) shift b units up and if b<0, then the graph of f(x) shift b units down.
It is given that the graph of f(x) shifts 4 units left and 2 units down. So, a=4 and b=-2.

![[\because f(x)=x^3]](https://tex.z-dn.net/?f=%5B%5Cbecause%20f%28x%29%3Dx%5E3%5D)

Therefore option B is correct.
We have events:
A - <span>customer orders a chicken sandwich
</span>B - <span>customer orders french fries
and probabilities:

so:

</span>
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)