3x²+5x=2
x(3x+5)=2
x=2 or 3x+5=2
x=3/5
Explanation:
Any function that has a derivative that changes sign will have an extreme value (maximum or minimum). If the derivative never changes sign, the function will not have any extreme values.
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Logarithmic, exponential, and certain trigonometric, hyperbolic, and rational functions are monotonic, having a derivative that does not change sign. Odd-degree polynomials may also have this characteristic, though not necessarily. These functions will not have maximum or minimum values.
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Certain other trigonometric, hyperbolic, and rational functions, as well as any even-degree polynomial function will have extreme values (maximum or minimum). Some of those extremes may be local, and some may be global. In the case of trig functions, they may be periodic.
Composite functions involving ones with extreme values may also have extreme values.
Answer:
The best estimate is 6
Step-by-step explanation:
1. Convert 1 3/4 to a whole fraction
7/4
2. Reciprocate 7/4
4/7
3. Multiply 90/7 by 4/7
360/49
4. Simplify/Solve
7.3
5. The best estimate is 6
If I am wrong please forgive and tell me in the comment section below otherwise bu-bye.
Answer:
x - 1\x + 3
Step-by-step explanation:
Factoring quadratic expressions with a Leading Coefficient of 1 → In the first equation, you have to find two numbers that when differed to 5, they also multiply to 6, and those numbers are 1 and 6. Now, the tough part for you might be figuring out which term gets which sign. Well, if you look at your MIDST term [5], you would know that the negative symbol goes to 1 [-1] and the positive symbol goes to 6, so your numerator is <em>[</em><em>x</em><em> </em><em>-</em><em> </em><em>1</em><em>]</em><em>[</em><em>x</em><em> </em><em>+</em><em> </em><em>6</em><em>]</em><em>.</em><em> </em>Now, for the second equation, it is applied the same way, but in this case, we need two numbers that when added to 9, they also multiply to 18, and those numbers are 3 and 6, and automatically receive positive symbols, so your denominator is <em>[</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em>]</em><em>[</em><em>x</em><em> </em><em>+</em><em> </em><em>6</em><em>]</em><em>.</em><em> </em>Now that we have our denominator and numerator, we now set it up: [x - 1][x + 6]\[x + 6][x + 3]. What do you see that is... MAGIC--AL? That is correct! The factors <em>x</em><em> </em><em>-</em><em> </em><em>6</em><em> </em>neutralize each other and are left with <em>x - 1\x + </em><em>3</em><em>.</em>
To be honest, if you had posted quadratic expressions with Leading Coefficients greater than 1, that would be a little bit more tough for you, meaning taking extra steps further, but if you post one in the future, it will be there to assist you because as always...,
I am joyous to assist anyone at any time.
If your looking for the y-intercept it is 4