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vfiekz [6]
3 years ago
9

Multiply these two together in simplest from

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

\frac{3x}{5(x+2)}

Step-by-step explanation:

Multiply the fractions by multiplying the numerators.

\frac{6x^2}{x(x-3)} * \frac{(x-3)}{10(x+2)} \\\\\frac{6x^2(x-3)}{10x(x-3)(x+2)} \\\\ \frac{6x}{10(x+2)} \\\\\frac{3x}{5(x+2)}

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3 years ago
0 = -1/14 x^2 + 4x +5<br><br> I need to solve for x but I don't get it, PLEASE EXPLAIN AND HELP!!
MariettaO [177]
Any time you have a fraction within an equation, multiply the entire equation by the denominator to clear the fraction. Since the lead term is negative, we can multiply that away as well
(-14) (0=-1/14x²+4x+5)      [now distribute]

0=x²-56x+70      [try to factor into binomials first]
Since 70 only has prime factors of 2·5·7, there is no combination which equals (-56). Use the quadratic formula, or complete the square. I'll use quadratic:

x=<u>-b+/-√(b²-4ac)</u>
            2a
a=1, b=(-56), c=70

x= <u>-(-56)+/- √((-56)²-4(1)(70)</u>
                  2(1)
x= <u>56+/- √(3136-280)
</u>               2
<u />x=<u>56+/-√(2856)</u>
             2
x=<u>56+/-√(2³·3·119)</u>
               2

x=<u>56+/-2√(714)</u>
             2

x=28+√714; x=28-√714



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Answer:

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Step-by-step explanation:

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Answer:c and then d

Step-by-step explanation

4 0
3 years ago
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