Answer:
<em>(A) 560 students</em>
<em>(B) P = 0.41</em>
Step-by-step explanation:
<em>(Please check the attached picture for more details)</em>
As given, a survey of 1000 students found that:
41% of the surveyed students were freshmen
=> 1000 x 41/100 = 410 surveyed students were freshmen
31% were juniors
=> 1000 x 31/100 = 310 surveyed students were junior
67% of surveyed students lived on the college campus
=> 1000 x 67/100 = 670 surveyed students lived on the campus
<em>(A) 260 of the surveyed students were freshmen living on the campus</em>
=> A = 410 - 260 = 150 surveyed students were freshmen NOT living on the campus
=> B = 670 - 260 = 410 surveyed students were not freshmen living on the campus
=> The number of surveyed students who were either freshmen or living on the campus:
N = A + B = 150 + 410 = 560
<em>(B) From a previous survey you know that of interviewed juniors, only 23% live on campus (we don't really need this)</em>
=>The probability a surveyed student is a junior or someone that lives on campus: P = (670 - 260)/1000 = 0.41
I hope this helps!
