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elixir [45]
4 years ago
14

What is the equation in point-slope form of the line passing through (0,6) and (1,3)

Mathematics
2 answers:
valina [46]4 years ago
5 0

Answer: y - 3 = -3(x - 1)

Step-by-step explanation:

You can start by finding the slope (m), \frac{y1 - y2}{x1 - x2}:

\frac{y1 - y2}{x1 - x2} = \frac{6 - 3}{0 - 1} = \frac{3}{-1} = -3.

Now, plug the range and one points into the point-slope form equation, y - y1 = m(x - x1):

y - y1 = m(x - x1)

y - 3 = -3(x - 1)

NISA [10]4 years ago
3 0

Answer:

y = -3x+6

Step-by-step explanation:

Coordinates are (0,6) and (1,3)

Slope = \frac{rise}{run}

Slope = \frac{3-6}{1-0}

Slope = -3

<u><em>Now, Finding b</em></u>

Taking any Point

Point = (x,y) = (0,6)

So, x = 0, y = 6

<em>Putting in slope-intercept form to find b</em>

y =mx+b

=> 6 = (-3)(0)+b

=> b = 6

<u><em>Now Putting slope and b in the formula to get the required slope-intercept form.</em></u>

y =mx+b

=> y = -3x+6

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