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horrorfan [7]
2 years ago
7

80/100 as a percentage​

Mathematics
2 answers:
lutik1710 [3]2 years ago
4 0

Answer:

<h2><em><u>80</u></em><em><u>%</u></em>.</h2>

Step-by-step explanation:

<em><u>Since</u></em><em><u>,</u></em>

Any number if divided by hundred then that no. is known as a <em><u>percentage</u></em>.

<em><u>Here</u></em><em><u>,</u></em>

<em><u>80</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>divided</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>100</u></em><em><u> </u></em><em><u>i</u></em><em><u>. </u></em><em><u>e</u></em><em><u>.</u></em>

80 / 100

= <em><u>80% (Ans)</u></em>

cluponka [151]2 years ago
3 0

Answer:

<h3>80\%</h3>

Step-by-step explanation:

Write the problem as a mathematical expression.

<h2>\frac{80}{100}</h2>

Convert to decimal.

<h3>0.8</h3>

Multiply 0.8 by 100 to convert to a percentage.

<h3>0.8 \times 100 </h3><h3>80\%</h3><h3>Hope it is helpful.....</h3>
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If a toy rocket is launched vertically upward from ground level with an initial velocity of 120 feet per second, then its height
german

Answer:

Time = 7.5\ seconds

Step-by-step explanation:

Given

Equation:\ h(t) = -16t^2 + 120t

Initial\ Velocity = 160ft/s

Required:

Determine the time taken to return to the ground

From the equation given; height (h) is a function of time (t)

When the rocket returns to the ground level, h(t) = 0

Substitute 0 for h(t) in the given equation

h(t) = -16t^2 + 120t

becomes

0 = -16t^2 + 120t

Solve for t in the above equation

-16t^2 + 120t = 0

Factorize the above expression

-4t(4t - 30) = 0

Split the expression to 2

-4t = 0\ or\ 4t - 30 = 0

Solving the first expression

-4t = 0

Divide both sides by -4

\frac{-4t}{-4} = \frac{0}{-4}

t = \frac{0}{-4}

t =0

Solving the second expression

4t - 30 = 0

Add 30 to both sides

4t - 30+30 = 0+30

4t  = 30

Divide both sides by 4

\frac{4t}{4}  = \frac{30}{4}

t  = \frac{30}{4}

t = 7.5

Hence, the values of t are:

t =0 and t = 7.5

t =0 shows the time before the launching the rocket

while

t = 7.5 shows the time after the rocket returns to the floor

5 0
2 years ago
Can U guys please help with this. :)
V125BC [204]

Answer:

x=0.9

Step-by-step explanation:

1.convert to improper fractions

4x+9/7/3=3x/0.5

2.Apply fraction cross multiply

(4x+9) * 0.5=7/3 * 3x

3. simplify

(4x+9) *0.5 =7x

4.Expand

2x+4.5=7x

5.Subtract 4.5 from both sides

2x=7x-4.5

6.Subtract 7x from both sides

2x-7=7x-4.5-7x

7.Simplify

-5x=-4.5

7.Divide by -5

x=0.9

 

5 0
2 years ago
How can you prove a triangle is isosceles? (4 points)
irina [24]
I think it is"A" hope it help
7 0
3 years ago
Read 2 more answers
Tell what whole number you can substitute for xx in the following list so the numbers are ordered from least to greatest. 1/x,x/
olasank [31]
X/3 has to be smaller tha 80%
so x can be 2 since 2/3=66% about
1/2 is less thn 2/3

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3 years ago
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Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
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