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4 years ago

PLEASE HELP

Mathematics

1 answer:

Mekhanik [1.2K]4 years ago

5 0

Answer:

a) 0.04

b) 0.08

Step-by-step explanation:

Part a)

Divide the price of a pack by the number of stickers in a pack to get the price of one sticker.

$2/50 = $0.04/1

One stickers costs $0.04.

Part b)

Calculate 80% more than the price of one sticker.

80% in decimal form is 0.8. 80% more than the price is calculated with the factor 1.8.

($0.04)(1.8) = $0.072

Round 0.072 up because is rounded down, the profit is less than 80%.

0.072 => 0.08

Each sticker would need to be sold for $0.08.

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3 years ago

A choice got cut off and it’s “-11x+6y=13”. Thank you! And this is a quiz and I have other questions on my account! I need fast

Marrrta [24]

–11x + 6y = –13

Solution:

The points on the line are (5, 7) and (–1, –4).

Here, $x_1=5, y_1=7, x_2=-1, y_2=-4$ \

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-4-7}{-1-5}$

$$m=\frac{-11}{-6}$

$$m=\frac{11}{6}$

Using point-slope formula,

$y-y_1=m(x-x_1)$

$$y-(-4)=\frac{11}{6} (x-(-1))$

$$y+4=\frac{11}{6} x+\frac{11}{6}$

Subtract 4 on both sides of the equation.

$$y=\frac{11}{6} x+\frac{11}{6}-4$

$$y=\frac{11}{6} x+\frac{11}{6}-\frac{24}{6}$

$$y=\frac{11}{6} x-\frac{13}{6}$

Multiply by 6 on both sides of the equation.

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3 0

4 years ago

Suppose that the inverse demand for a downstream firm is P = 150 − Q. Its upstream division produces a critical input with costs

kozerog [31]

Answer:

The marginal revenue is $MT_d = 116.66$

Step-by-step explanation:

From the question we are told that

The inverse demand for a downstream firm is $P = 150 -Q$

The cost of the critical input produced by upstream division is $CU(Q_d) = 5(Q_d)^2$

The cost of the critical input produced by downstream firm is Cd(Q) = 10Q

Generally

The marginal revenue of the downstream firm - The marginal cost of the downstream firm = Net marginal revenue of downstream

i.e

$MR_d - MC_d = MT_d$

Also

The marginal revenue of the downstream firm - The marginal cost of the downstream firm = Marginal upstream cost

i.e

$MR_d - MC_d = MC_u$

Generally the total revenue of downstream firm is mathematically represented as

$TR = P * Q$

Here Q stands for quantity produced by the downstream firm and TR is the total revenue

$TR = [150 - Q] * Q$

=> $TR = 150Q - Q^2$

Generally the marginal revenue of the downstream firm is mathematically evaluated as

$MR_d =\frac{d (TR)}{d Q} = 150 - 2Q$

Generally marginal downstream first cost is mathematically evaluated as

$MC_d = \frac{d(Cd(Q)) }{dQ} = 10$

Generally the net marginal revenue of the downstream firm is mathematically represented as

$150 - 2Q -10 = MT_d$

=> $MT_d = 140 - 2Q$

Generally the marginal upstream cost is mathematically represented a

$MC _u =\frac{d [CU(Q_d)]}{dQ_d} = 10(Q_d)$

Generally $Q_d = Q$ this because $Q_d$ represents the quantity produced by the downstream firm and also Q is associated with the cost of the downstream quantity

$MC _u =\frac{d [CU(Q)]}{dQ} = 10Q$

=> $10(Q) = 140 -2Q$

=> $Q = 11.67$

So the net marginal revenue of the downstream firm is mathematically represented as

=> $MT_d = 140 - 2(11.67)$

=> $MT_d = 116.66$

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3 years ago

Find the perimeter AND area of the parallelogram ABCD. Show all work

stiks02 [169]

Answer-

The perimeter and area of the parallelogram are 19.74 units and 15 sq. units respectively.

Solution-

The co-ordinates of the vertices are,

A = (-2, 3)

B = (4, 0)

C = (1, -1)

D = (-5, 2)

E = (-3, 1)

We can get the side length of the parallelogram by calculating the respective distances by applying distance formula,

$\overline{CD}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-5-1)^2+(2+1)^2}=\sqrt{(-6)^2+(3)^2}=\sqrt{36+9}=\sqrt{45}=3\sqrt5$

$\overline{AD}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-2+5)^2+(3-2)^2}=\sqrt{(3)^2+(1)^2}=\sqrt{9+1}=\sqrt{10}$

$\overline{AE}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-2+3)^2+(3-1)^2}=\sqrt{(1)^2+(2)^2}=\sqrt{1+4}=\sqrt{5}$

Perimeter of the parallelogram ABCD is,

$=2(\overline{AD}+\overline{CD})\\\\=2(\sqrt{10}+3\sqrt5)\\\\=19.74\ units$

Area of the parallelogram ABCD is,

$=\overline{CD}\times \overline{AE}\\\\=3\sqrt5\times \sqrt{5}\\\\=3\times 5\\\\=15\ sq.unit$

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3 years ago